如何获取查询的这一部分以按时间范围获取值?
表格示例:
select * from tablename where timeregister between '2017-01-11' And '2017-01-30';
我怎样才能让timeregister 是最后7 天?我正在尝试这个:
select * from tablename where timeregister(NOW(), timeregister) <= 7;
如何获取查询的这一部分以按时间范围获取值?
表格示例:
select * from tablename where timeregister between '2017-01-11' And '2017-01-30';
我怎样才能让timeregister 是最后7 天?我正在尝试这个:
select * from tablename where timeregister(NOW(), timeregister) <= 7;
用这个 :
SELECT * FROM table WHERE timeregister >= DATE(NOW()) - INTERVAL 7 DAY
尝试这个....
<?php
$s_date = date('Y-m-d');
$e_date = date('Y-m-d',strtotime('+7 days'));
$sql = 'SELECT * FROM tablename WHERE DATE_FORMAT(timeregister, "%Y-%m-%d") BETWEEN "'.$s_date.'" AND "'.$e_date.'"';
?>
您使用的是 MSSQL 还是 MYSQL?如果是 MSSQL,那么您可以使用 DATEADD 函数。请参阅下面的脚本:
SELECT * FROM table WHERE timeregister between DATEADD(DD,-7,GETDATE()) and GETDATE()