2

我正在尝试将媒体从手机播放到 ExoPlayer。我正在从Environment.getExternalStorageDirectory().getAbsoluteFile();

每当我尝试播放媒体时-我都会收到此错误-

源错误 com.google.android.exoplayer2.upstream.HttpDataSource$HttpDataSourceException:无法连接到 /storage/emulated/0/Download/big_buck_bunny_720p_1mb.mp4

还,

引起:java.net.MalformedURLException:无协议:/storage/emulated/0/Download/big_buck_bunny_720p_1mb.mp4

我在这里经过 UriMediaSource mediaSource = buildMediaSource(Uri.parse(link));

此方法使用 Uri

private MediaSource buildMediaSource(Uri uri) {
    DataSource.Factory dataSourceFactory = new 
DefaultHttpDataSourceFactory("ua", BANDWIDTH_METER);
    DashChunkSource.Factory dashChunkSourceFactory = new 
DefaultDashChunkSource.Factory(dataSourceFactory);
    return new DashMediaSource(uri, dataSourceFactory, 
dashChunkSourceFactory, null, null);
}

这就是我获取链接的方式

arrayList1 = video(Environment.getExternalStorageDirectory().getAbsoluteFile());
protected ArrayList<File> video(File file) {
    File[] filename = file.listFiles();
    ArrayList<File>  arrayList2 = new ArrayList<File>();
    try {
        for (File file1 : filename) {
            if (file1.isDirectory()) {
                arrayList2.addAll(video(file1));
            } else {
                if (file1.getName().endsWith(".mp4")) {
                    arrayList2.add(file1);
                }
            }
        }
    }catch (Exception e){
    }
    return arrayList2;
}
4

1 回答 1

6

使用FileDataSource。以下代码段从资产 uri(如 file:///android_asset/video.mp4 或其他文件 uri)创建 mp4 的 MediaSource:

  private MediaSource buildMediaSource(Uri uri) {
    DataSource.Factory dataSourceFactory = new FileDataSourceFactory();
    return new ExtractorMediaSource(uri, dataSourceFactory, 
        new DefaultExtractorsFactory(), null, null);
  }
于 2017-10-29T23:22:16.170 回答