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我有两张桌子 - EducatorsFaculties

CREATE TABLE [dbo].[Educators]
(
    [UserId] [nvarchar](128) NOT NULL,
    [FacultyId] [smallint] NOT NULL,
    [InstitutionUserId] [nvarchar](128) NOT NULL,

    CONSTRAINT [PK_Educators] 
        PRIMARY KEY CLUSTERED ([UserId] ASC)
)

CREATE TABLE [dbo].[Faculties]
(
    [InstitutionUserId] [nvarchar](128) NOT NULL,
    [FacultyId] [smallint] NOT NULL,

    CONSTRAINT [PK_UserFaculties] 
        PRIMARY KEY CLUSTERED ([InstitutionUserId] ASC, [FacultyId] ASC)
)

该表Faculties具有由两列 (InstitutionUserIdFacultyId) 组成的复合主键。我在表中也有相同的列Educators。我想用外键将这两个表链接在一起。

所以,这是我的查询:

ALTER TABLE [dbo].[Educators] WITH CHECK 
    ADD CONSTRAINT [FK_Educators_FacultyId_Faculties_FacultyId] 
    FOREIGN KEY ([FacultyId], [InstitutionUserId])
    REFERENCES [dbo].[Faculties] ([FacultyId], [InstitutionUserId])

但我收到此错误消息:

消息 1776,级别 16,状态 0,第 7 行
引用表 'dbo.Faculties' 中没有与外键 'FK_Educators_FacultyId_Faculties_FacultyId' 中的引用列列表匹配的主键或候选键。

消息 1750,级别 16,状态 1,第 7 行
无法创建约束或索引。请参阅以前的错误。

如何解决这个问题呢?

4

2 回答 2

2

您的表及其约束看起来不错。我能看到的唯一问题是主键中列的顺序

CONSTRAINT [PK_UserFaculties] PRIMARY KEY CLUSTERED 
(
    [InstitutionUserId] ASC,
    [FacultyId] ASC
)

与您在外键约束中声明的顺序不同

ALTER TABLE [dbo].[Educators]  WITH CHECK ADD  CONSTRAINT [FK_Educators_FacultyId_Faculties_FacultyId] FOREIGN KEY([FacultyId], [InstitutionUserId])
REFERENCES [dbo].[Faculties] ([FacultyId], [InstitutionUserId])

尝试更改外键声明中列的顺序,如下所示:

ALTER TABLE [dbo].[Educators]  WITH CHECK ADD  CONSTRAINT [FK_Educators_FacultyId_Faculties_FacultyId] FOREIGN KEY([InstitutionUserId], [FacultyId])
REFERENCES [dbo].[Faculties] ([InstitutionUserId], [FacultyId])
于 2017-08-20T12:34:05.970 回答
1

键的顺序应与定义的顺序相同:

ALTER TABLE dbo.Educators
    ADD CONSTRAINT FK_Educators_FacultyId_Faculties_FacultyId
        FOREIGN KEY(InstitutionUserId, FacultyId)
            REFERENCES dbo.Faculties(InstitutionUserId, FacultyId);
于 2017-08-20T12:29:48.897 回答