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截图。我正在寻找右侧的图表,但我得到的是左侧的图表。我是 Graphviz 的新手。我还必须制作节点 1 和 2,因为我无法模仿右侧的图像。我的端子形状也不完全相同。有人帮我解决这个问题。我的代码到现在:

digraph M
{
  style=filled;
  graph [splines = headport];

  START->1
  1->"Is COUNT\nan even\nnumber?"
  "Is COUNT\nan even\nnumber?"->"SUM = SUM +\nCOUNT" [label=TRUE]
  "SUM = SUM +\nCOUNT"->2
  "Is COUNT\nan even\nnumber?"->2 [label=FALSE]
  2->"COUNT = COUNT+1"
  "COUNT = COUNT+1"->"IS COUNT >\n20"
  "IS COUNT >\n20"->1 [label=FALSE]
  "IS COUNT >\n20"->STOP[label=TRUE]


  "Is COUNT\nan even\nnumber?"[shape=diamond]
  "SUM = SUM +\nCOUNT"[shape=rectangle]
  "IS COUNT >\n20"[shape=diamond]
  "COUNT = COUNT+1"[shape=rectangle]
  1[shape=circle]
  2[shape=circle]
  START[shape=record, style="rounded"]
  STOP[shape=record, style="rounded"]
}
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1 回答 1

1

我对您的图表进行了一些更改,以使您更接近。样条线的折线并更改了 1 和 2 节点的属性以更接近您的目标。显然不是完美的,但希望能够更好地帮助和建议其他方法,您可以在不进行重大重新设计的情况下进一步改进它。

digraph M
{
  style=filled;
  graph [splines = headport splines=polyline];

  START->1
  1->"Is COUNT\nan even\nnumber?"
  "Is COUNT\nan even\nnumber?"->"SUM = SUM +\nCOUNT" [label=TRUE]
  "SUM = SUM +\nCOUNT"->2
  "Is COUNT\nan even\nnumber?"->2 [label=FALSE]
  2->"COUNT = COUNT+1" 
  "COUNT = COUNT+1"->"IS COUNT >\n20"
  "IS COUNT >\n20"->1 [label=FALSE tailport=e]
  "IS COUNT >\n20"->STOP[label=TRUE ]


  "Is COUNT\nan even\nnumber?"[shape=diamond]
  "SUM = SUM +\nCOUNT"[shape=rectangle]
  "IS COUNT >\n20"[shape=diamond]
  "COUNT = COUNT+1"[shape=rectangle headport=n]
  1[shape=point size="0,0" label=""]
  2[shape=point size="0,0" label=""]
  START[shape=record, style="rounded"]
  STOP[shape=record, style="rounded"]
}
于 2017-08-18T13:39:03.280 回答