android - 如何使用 Nested RecyclerView 获得预期设计

Question

我的 JSON 格式如下，我可以使用改造将这个 JSON 数据获取到 android 中，但是在获取之后我没有得到如何在 Vertical RecyclerView 的 Horizo​​ntal RecyclerView 中显示它，如下图所示，我想要 AAAAA显示而不是 Section1 和 name1 而不是 item1 和要显示的相应图像。请帮我为此编写android代码。

  {"result":
           {"AAAAA":[{"firm_name":"name1","image_path":"1.jpg"},
                     {"firm_name":"name2","image_path":"2.jpg"}],
           "BBBBB":[{"firm_name":"name1","image_path":"1.jpg"}],
           "CCCCC":[{"firm_name":"name1","image_path":"1.jpg"}],
           "DDDDD":[{"firm_name":"name1","image_path":"1.jpg"}],
           "EEEEE":[{"firm_name":"name1","image_path":"1.jpg"}]
           }
     }
 This is my Json code

这是我的 pojo 课

   package com.example;

   import com.google.gson.annotations.Expose;
   import com.google.gson.annotations.SerializedName;

   public class Example {

   @SerializedName("result")
   @Expose
   private Result result;

   public Result getResult() {
   return result;
   }

   public void setResult(Result result) {
   this.result = result;
   }
   }

---

package com.example;

import java.util.List;
import com.google.gson.annotations.Expose;
import com.google.gson.annotations.SerializedName;

public class Result {

@SerializedName("AAAAA")
@Expose
private List<AAAAA> aAAAA = null;
@SerializedName("BBBBB")
@Expose
private List<BBBBB> bBBBB = null;
@SerializedName("CCCCC")
@Expose
private List<Object> cCCCC = null;
@SerializedName("DDDDD")
@Expose
private List<Object> dDDDD = null;
@SerializedName("EEEEE")
@Expose
private List<Object> eEEEE = null;

public List<AAAAA> getAAAAA() {
return aAAAA;
}

public void setAAAAA(List<AAAAA> aAAAA) {
this.aAAAA = aAAAA;
}

public List<BBBBB> getBBBBB() {
return bBBBB;
}

public void setBBBBB(List<BBBBB> bBBBB) {
this.bBBBB = bBBBB;
}

public List<Object> getCCCCC() {
return cCCCC;
}

public void setCCCCC(List<Object> cCCCC) {
this.cCCCC = cCCCC;
}

public List<Object> getDDDDD() {
return dDDDD;
}

public void setDDDDD(List<Object> dDDDD) {
this.dDDDD = dDDDD;
}

public List<Object> getEEEEE() {
return eEEEE;
}

public void setEEEEE(List<Object> eEEEE) {
this.eEEEE = eEEEE;
}
}