7

给定一个如下所示的 xml 文档：

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE properties SYSTEM "http://java.sun.com/dtd/properties.dtd">
<properties>
    <entry key="agentType">STANDARD</entry>
    <entry key="DestinationTransferStates"></entry>
    <entry key="AgentStatusPublishRate">300</entry>
    <entry key="agentVersion">f000-703-GM2-20101109-1550</entry>
    <entry key="CommandTimeUTC">2010-12-24T02:25:43Z</entry>
    <entry key="PublishTimeUTC">2010-12-24T02:26:09Z</entry>
    <entry key="queueManager">AGENTQMGR</entry>
</properties>

我想打印“key”属性和元素的值，所以它看起来像这样：

agentType = STANDARD
DestinationTransferStates = 
AgentStatusPublishRate = 300
agentVersion = f000-703-GM2-20101109-1550
CommandTimeUTC = 2010-12-24T02:25:43Z
PublishTimeUTC = 2010-12-24T02:26:09Z
queueManager = AGENTQMGR

我可以使用以下代码毫无问题地打印节点值：

XPathFactory factory = XPathFactory.newInstance();
XPath xpath = factory.newXPath();
XPathExpression expr = xpath.compile("//properties/entry/text()");

Object result = expr.evaluate(doc, XPathConstants.NODESET);
NodeList nodes = (NodeList) result;
for (int i = 0; i < nodes.getLength(); i++) {
    System.out.println(nodes.item(i).getNodeValue()); 
}

我可以通过更改 xpath 表达式和节点方法来打印“key”属性的值，如下所示：

XPathFactory factory = XPathFactory.newInstance();
XPath xpath = factory.newXPath();
XPathExpression expr = xpath.compile("//properties/entry");
Object result = expr.evaluate(doc, XPathConstants.NODESET);
NodeList nodes = (NodeList) result;
for (int i = 0; i < nodes.getLength(); i++) {
    System.out.println(nodes.item(i).getAttributes().getNamedItem("key").getNodeValue()); 
}

似乎有一种方法可以在单个evaluate. 我总是可以评估两个 NodeList 并使用公共索引遍历它们，但我不确定它们是否保证以相同的顺序返回。任何建议表示赞赏。

4

1 回答 1

11

怎么样getTextContent()？这应该做的工作。

Object result = expr.evaluate(doc, XPathConstants.NODESET);
NodeList nodes = (NodeList) result;
for (int i = 0; i < nodes.getLength(); i++)
{
    Node currentItem = nodes.item(i);
    String key = currentItem.getAttributes().getNamedItem("key").getNodeValue();
    String value = currentItem.getTextContent();

    System.out.printf("%1s = %2s\n", key, value);
}

有关详细信息，请参阅 .java 文档getTextContent()。我希望这能帮到您。

于 2010-12-24T12:40:30.253 回答