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我有以下查询（更新见下文）：

SELECT 

i0_.id AS id_0, 
i0_.address AS address_1, 
i1_.name AS name_2, 
c2_.name AS name_3, 
c3_.code AS code_4, 
l4_.iso AS iso_5, 
c5_.id AS id_6, 
c6_.name AS name_7, 
i7_.identifier AS identifier_8 

FROM institutions i0_ 
LEFT JOIN institution_languages i1_ ON (i1_.institution_id = i0_.id) 
LEFT JOIN countries c3_ ON (c3_.id = i0_.country_id) 
LEFT JOIN country_languages c2_ ON (c2_.country_id = c3_.id) 
LEFT JOIN country_spoken_languages c8_ ON (c8_.country_id = c3_.id) 
LEFT JOIN cities c5_ ON (c5_.id = i0_.city_id) 
LEFT JOIN city_languages c6_ ON (c6_.city_id = c5_.id) 
LEFT JOIN languages l4_ ON (l4_.id = i1_.language_id) 
LEFT JOIN institution_types i7_ ON (i0_.institution_type_id = i7_.id) 

WHERE c8_.is_primary = 1 
AND c8_.language_id = l4_.id 
AND c2_.language_id = 546 
AND i7_.identifier = "work_place" 
GROUP BY id_6 #here is the issue...

更新查询

SELECT 
i0_.id AS id_0, 
i0_.address AS address_1, 
i1_.name AS name_2, 
c2_.name AS name_3, 
c3_.code AS code_4, 
c4_.name AS name_5, 
i5_.identifier AS identifier_6 

FROM institutions i0_ 

LEFT JOIN institution_languages i1_ ON (i1_.institution_id = i0_.id) 
LEFT JOIN countries c3_ ON (c3_.id = i0_.country_id) 
LEFT JOIN country_languages c2_ ON (c2_.country_id = c3_.id AND c2_.language_id = ?) 
LEFT JOIN country_spoken_languages c6_ ON (c6_.country_id = c3_.id AND c6_.language_id = ? AND c6_.is_primary = ?) 
LEFT JOIN city_languages c4_ ON (c4_.city_id = i0_.city_id) 
LEFT JOIN institution_types i5_ ON (i0_.institution_type_id = i5_.id) 

WHERE i5_.identifier = ? 
GROUP BY i0_.city_id

此查询与 GROUP_BY 存在问题，我不知道如何解决：

1055 - SELECT 列表的表达式 #1 不在 GROUP BY 子句中，并且包含非聚合列 'database.i0_.id'

功能上依赖于 GROUP BY 子句中的列；这与 sql_mode=only_full_group_by 不兼容

我知道这可以通过设置 only_full_group_by 轻松解决，但是我可以对我的查询做些什么来使其正常工作而不必修改我服务器上的 MySQL 设置？

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2 回答 2

3

如果你不想改变 sql_mode=only_full_group_by

您可以简单地将聚合函数添加到 group by 不涉及的列（例如 min() 或 max()

（在以前的版本中，此列的结果是不可预测的。通过这种方式，您可以分配一个规则来获取这些列的值）

SELECT 
  i0_.id AS id_0, 
  min(i0_.address AS) address_1, 
  min(i1_.name) AS name_2, 
  min(c2_.name )AS name_3, 
  min(c3_.code) AS code_4, 
  min(c4_.name) AS name_5, 
  min(i5_.identifier) AS identifier_6 

FROM institutions i0_ 

LEFT JOIN institution_languages i1_ ON (i1_.institution_id = i0_.id) 
LEFT JOIN countries c3_ ON (c3_.id = i0_.country_id) 
LEFT JOIN country_languages c2_ ON (c2_.country_id = c3_.id AND c2_.language_id = ?) 
LEFT JOIN country_spoken_languages c6_ ON (c6_.country_id = c3_.id AND c6_.language_id = ? AND c6_.is_primary = ?) 
LEFT JOIN city_languages c4_ ON (c4_.city_id = i0_.city_id) 
LEFT JOIN institution_types i5_ ON (i0_.institution_type_id = i5_.id) 

WHERE i5_.identifier = ? 
GROUP BY i0_.city_id
于 2017-05-13T11:22:06.337 回答
0

我认为您应该至少在选择字段中使用聚合函数才能使查询正常工作，请参见下面我尝试使用表“客户”和“订单”中的示例数据库“经典模型”：

select c.customerNumber, sum(o.orderNumber)
from customers c
join orders o
on(c.customerNumber = o.customerNumber)
group by c.customerNumber;

返回结果，但如果我删除函数'sum（）'，输出如下：

错误 1055 (42000)：SELECT 列表的表达式 #2 不在 GROUP BY 子句中，并且包含在功能上不依赖于 GROUP BY 子句中的列的非聚合列“classicmodels.o.orderNumber”；这与 sql_mode=only_full_group_by 不兼容

于 2017-05-13T13:27:48.527 回答