-5

我在这里问的问题很容易解决。代码工作正常，但这个警告让我很烦！

//initailize array elements
    char ZeroA[6]   = {0xC0,0x07,0x40,0x04,0xC0,0x07,};
    char OneA[6]    = {0x80, 0x04, 0xC0, 0x07, 0x00, 0x04,};
    char TwoA[6]    = {0x40, 0x07, 0x40, 0x05, 0xC0, 0x05,};
    char ThreeA[6]  = {0x40, 0x05, 0x40, 0x05, 0xC0, 0x07,};
    char FourA[6]   = {0x80, 0x03, 0x00, 0x02, 0x80, 0x07,};
    char FiveA[6]   = {0xC0, 0x05, 0x40, 0x05, 0x40, 0x07,};
    char SixA[6]    = {0xC0,0x05,0x40,0x05,0x40,0x07,}; 
    char SevenA[6]  = {0x40,0x04,0x40,0x03,0xC0,0x00,};
    char EightA[6]  = {0xC0,0x07,0x40,0x05,0xC0,0x07,};
    char NineA[6]   = {0xC0,0x05,0x40,0x05,0xC0,0x07,};
    char TenA[6]    = {0x00,0x01,0x80,0x03,0x00,0x01,};

int *mCount;     //address holder
char var = 4;    //Just random number for illustration

int *XYZ[11]={&ZeroA,&OneA,&TwoA,&ThreeA,&FourA,&FiveA,&SixA,&SevenA,&EightA,&NineA,&TenA};

mCount = XYZ[Var];
4

2 回答 2

0

随着 amine.ahd 的继续， mCount 需要是一个 char 指针。

char *mCount;     //address holder

mCount = XYZ[var];   

int i = 0;

for( i = 0; i < 6; i ++ )
 printf( "%c ", mCount[i] );

插入几行代码进行测试。虽然它打印了白色字符，但它似乎正在工作。更重要的是，没有编译警告。

于 2017-05-04T21:35:53.423 回答
-2

ZeroAchar所以一个是指向元素 数组的指针。&ZeroA保存指向数组的指针的地址，ZeroA因此您需要保存它char **

在您的示例中执行此操作的正确方法是这样的： char *XYZ[11]={ZeroA,OneA,TwoA,ThreeA,FourA,FiveA,SixA,SevenA,EightA,NineA,TenA};

于 2017-05-04T20:35:58.277 回答