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假设数据存储在 4.7 MB 的 CD 上,每张重 50 克。假设一架飞机以 1500 公里/小时的速度在 5000 公里的距离上携带 10^4 公斤的这些 CD。什么是数据传输速率(以比特/比特为单位)这个系统的第二个?
我不会称其为“数据传输”,但是:
Amount of CD's = 10^4 / 0.05 = 2e5
Amount of bits = 4.7e6 * 8 * amount of CD's = 7.52e12
Seconds to carry data = 5000e3 / (1500/3.6) = 12000 seconds
(7.52 * 10^12)/ 12000) = 0.6Gbits/s