24

我知道这可以使用 PHPparse_url和parse_str函数轻松完成：

$subject = "http://www.youtube.com/watch?v=z_AbfPXTKms&NR=1";
$url = parse_url($subject);
parse_str($url['query'], $query);
var_dump($query);

但是如何使用 Python 来实现呢？我可以做urlparse，但下一步怎么办？

4

14 回答 14

63

我创建了没有正则表达式的 youtube id 解析器：

import urlparse

def video_id(value):
    """
    Examples:
    - http://youtu.be/SA2iWivDJiE
    - http://www.youtube.com/watch?v=_oPAwA_Udwc&feature=feedu
    - http://www.youtube.com/embed/SA2iWivDJiE
    - http://www.youtube.com/v/SA2iWivDJiE?version=3&hl=en_US
    """
    query = urlparse.urlparse(value)
    if query.hostname == 'youtu.be':
        return query.path[1:]
    if query.hostname in ('www.youtube.com', 'youtube.com'):
        if query.path == '/watch':
            p = urlparse.parse_qs(query.query)
            return p['v'][0]
        if query.path[:7] == '/embed/':
            return query.path.split('/')[2]
        if query.path[:3] == '/v/':
            return query.path.split('/')[2]
    # fail?
    return None
于 2011-10-29T02:04:10.737 回答
46

Python 有一个用于解析 URL 的库。

import urlparse
url_data = urlparse.urlparse("http://www.youtube.com/watch?v=z_AbfPXTKms&NR=1")
query = urlparse.parse_qs(url_data.query)
video = query["v"][0]
于 2010-12-05T00:02:43.443 回答
14

这是 Mikhail Kashkin 的解决方案的 Python3 版本，添加了场景。

from urllib.parse import urlparse, parse_qs
from contextlib import suppress


# noinspection PyTypeChecker
def get_yt_id(url, ignore_playlist=False):
    # Examples:
    # - http://youtu.be/SA2iWivDJiE
    # - http://www.youtube.com/watch?v=_oPAwA_Udwc&feature=feedu
    # - http://www.youtube.com/embed/SA2iWivDJiE
    # - http://www.youtube.com/v/SA2iWivDJiE?version=3&hl=en_US
    query = urlparse(url)
    if query.hostname == 'youtu.be': return query.path[1:]
    if query.hostname in {'www.youtube.com', 'youtube.com', 'music.youtube.com'}:
        if not ignore_playlist:
        # use case: get playlist id not current video in playlist
            with suppress(KeyError):
                return parse_qs(query.query)['list'][0]
        if query.path == '/watch': return parse_qs(query.query)['v'][0]
        if query.path[:7] == '/watch/': return query.path.split('/')[1]
        if query.path[:7] == '/embed/': return query.path.split('/')[2]
        if query.path[:3] == '/v/': return query.path.split('/')[2]
   # returns None for invalid YouTube url
于 2019-01-26T23:19:43.947 回答
13

这是 RegExp 它涵盖了这些情况在此处输入图像描述

((?<=(v|V)/)|(?<=be/)|(?<=(\?|\&)v=)|(?<=embed/))([\w-]+)

于 2015-01-06T09:55:59.933 回答
4 
match = re.search(r"youtube\.com/.*v=([^&]*)", "http://www.youtube.com/watch?v=z_AbfPXTKms&test=123")
if match:
    result = match.group(1)
else:
    result = ""

未经测试。

于 2010-12-05T00:20:53.677 回答
3

您可以使用

from urllib.parse import urlparse

url_data = urlparse("https://www.youtube.com/watch?v=RG9TMn1FJzc")
print(url_data.query[2::])
于 2020-08-30T22:53:46.517 回答
2

您可以尝试将正则表达式用于 youtube 视频 ID：

# regex for the YouTube ID: "^[^v]+v=(.{11}).*"
result = re.match('^[^v]+v=(.{11}).*', url)
print result.group(1)
于 2010-12-05T00:18:36.300 回答
1

不需要正则表达式。分开，拿第二?个，分开=，拿第二个，分开&，拿第一个。

于 2010-12-05T00:00:54.367 回答
1

当这些参数可以以任何顺序出现时，拆分字符串是一个非常糟糕的主意。坚持使用 urlparse：

from urllib.parse import parse_qs, urlparse

vid = parse_qs(urlparse(url).query).get('v')
于 2021-07-28T07:50:42.000 回答
1

我用这个很棒的包pytube。$ pip install pytube

#Examples
url1='http://youtu.be/SA2iWivDJiE'
url2='http://www.youtube.com/watch?v=_oPAwA_Udwc&feature=feedu'
url3='http://www.youtube.com/embed/SA2iWivDJiE'
url4='http://www.youtube.com/v/SA2iWivDJiE?version=3&amp;hl=en_US'
url5='https://www.youtube.com/watch?v=rTHlyTphWP0&index=6&list=PLjeDyYvG6-40qawYNR4juzvSOg-ezZ2a6'
url6='youtube.com/watch?v=_lOT2p_FCvA'
url7='youtu.be/watch?v=_lOT2p_FCvA'
url8='https://www.youtube.com/watch?time_continue=9&v=n0g-Y0oo5Qs&feature=emb_logo'

urls=[url1,url2,url3,url4,url5,url6,url7,url8]

#Get youtube id
from pytube import extract
for url in urls:
    id=extract.video_id(url)
    print(id)

输出

SA2iWivDJiE
_oPAwA_Udwc
SA2iWivDJiE
SA2iWivDJiE
rTHlyTphWP0
_lOT2p_FCvA
_lOT2p_FCvA
n0g-Y0oo5Qs
于 2021-02-24T22:36:35.260 回答
0

我用这个

def getId(videourl):
    vidid=videourl.find('watch?v=')
    Id = videourl[vidid+8:vidid+19]
    if vidid==-1:
        vidid=videourl.find('be/')
        Id=videourl[vidid+3:]
    return Id
于 2022-03-02T09:44:03.540 回答
0

尽管这将进行搜索查询，但会为您提供id：

from youtube_search import YoutubeSearch    
results = YoutubeSearch('search terms', max_results=10).to_json()    
print(results)
于 2020-03-01T14:13:25.810 回答
0 
url = "http://www.youtube.com/watch?v=z_AbfPXTKms&NR=1"
parsed = url.split("?")
videoId = parsed[1]
print(videoId)

这适用于各种 YouTube 视频链接。

于 2020-08-30T23:02:13.467 回答
0

我很晚了，但我使用这个片段来获取视频ID。

def video_id(url: str) -> str:
    """Extract the ``video_id`` from a YouTube url.
    This function supports the following patterns:
    - :samp:`https://youtube.com/watch?v={video_id}`
    - :samp:`https://youtube.com/embed/{video_id}`
    - :samp:`https://youtu.be/{video_id}`
    :param str url:
        A YouTube url containing a video id.
    :rtype: str
    :returns:
        YouTube video id.
    """
    return regex_search(r"(?:v=|\/)([0-9A-Za-z_-]{11}).*", url, group=1)

def regex_search(pattern: str, string: str, group: int):
    """Shortcut method to search a string for a given pattern.
    :param str pattern:
        A regular expression pattern.
    :param str string:
        A target string to search.
    :param int group:
        Index of group to return.
    :rtype:
        str or tuple
    :returns:
        Substring pattern matches.
    """
    regex = re.compile(pattern)
    results = regex.search(string)
    if not results:
        return False

    return results.group(group)
于 2021-07-03T14:20:19.480 回答