mysql - Mysql如何将字符串转换为日期时间格式

Question

我有这个文件 csv：

20170117-00:00:6    3087A6B282A46C  124.191.134.139 2746    256 63628   
20170117-00:00:53   330391C9F58B5A  120.18.97.172   2746    257 43077
20170117-00:02:27   3303CD14BD40C8  110.147.131.78  2746    256 63628
20170117-00:02:00   3304B3CD448E4F  189.35.218.62   2746    255 43074

我正在尝试使用加载数据本地 infile 上传它，但我在时间列中仅获得 Null 值。这是我的代码（时间是表列的名称）

LOAD DATA LOCAL INFILE 'path.log'
                INTO TABLE Clicks
                CHARACTER SET latin1
                FIELDS TERMINATED BY '\t'

                ENCLOSED BY '"'
                LINES TERMINATED BY '\n'
                IGNORE 1 ROWS

                SET Time= STR_TO_DATE(@Time,'%Y%m%d-%H:%i:%s')
                ;

Answer 1

这是您应该使用的语法：

LOAD DATA LOCAL INFILE 'path.log'
INTO TABLE Clicks
CHARACTER SET latin1
FIELDS TERMINATED BY '\t'
ENCLOSED BY '"'
LINES TERMINATED BY '\n'
IGNORE 1 ROWS
(@Time, column2, column3, column4, column5)         -- read time data into @Time
SET column1 = STR_TO_DATE(@Time, '%Y%m%d-%H:%i:%s') -- then set column1

我认为@Time变量从未被设置为每条正在读取的记录，因此您进入NULL了第一列。

Answer 2

尝试这个

LOAD DATA LOCAL INFILE 'path.log'
                INTO TABLE Clicks
                CHARACTER SET latin1
                FIELDS TERMINATED BY '\t'

                ENCLOSED BY '"'
                LINES TERMINATED BY '\n'
                IGNORE 1 ROWS

                SET TIME= CONCAT(SUBSTRING(@Time,1,4),'-',SUBSTRING(@Time,5,2),'-',SUBSTRING(@Time,7,2),' ',REPLACE(@Time,CONCAT(SUBSTRING_INDEX(@Time, '-',1),'-'),''))