1

我有一个从输入流形成的 KML 层,如下所示:

private KmlLayer layer;
inputStream = new URL("urlHERE").openStream();
layer = new KmlLayer(mMap, inputStream, getApplicationContext());

我想遍历这一层中的每个标记,并检查它是否在我当前位置的一定距离内,只有在它是时才显示它。

这是我目前用来获取标记的纬度/经度的代码。

for (KmlPlacemark placemark: layer.getPlacemarks()) {


            String s = placemark.getGeometry().getGeometryObject().toString();
            Log.d("placemarks",s);
            String start = "(";
            String end = ")";
            String latlngvalue = s.substring(s.indexOf(start)+1,s.lastIndexOf(end));
            String[] strngs = latlngvalue.split(",");
            double placemarkerLat = Double.parseDouble(strngs[0]);
            double placemarkerLong = Double.parseDouble(strngs[2]);
            markerLocation.setLatitude(placemarkerLat);
            markerLocation.setLongitude(placemarkerLong);

我想要做的是在 ArrayList 中添加每个标记的信息,如果它们在用户的一定距离内,然后将标记添加到地图上。

4

1 回答 1

0

检查这条线

currLocationMarker = mGoogleMap.addMarker(markerOptions); //你的答案在这里

 @Override
 public void onLocationChanged(Location location) {

    mGoogleMap.clear();
    mHashMap.clear();

    allMarkersLists.clear();
    favouriteGpList.clear();

    //place marker at current position
    //mGoogleMap.clear();
    if (currLocationMarker != null) {
        currLocationMarker.remove();
    }

    latitude = location.getLatitude();
    longitude = location.getLongitude();
    latLng = new LatLng(location.getLatitude(), location.getLongitude());

    markerOptions = new MarkerOptions();
    markerOptions.position(latLng);
    markerOptions.icon(BitmapDescriptorFactory.defaultMarker(BitmapDescriptorFactory.HUE_GREEN)).draggable(true);
    currLocationMarker = mGoogleMap.addMarker(markerOptions); //YOUR ANSWER HERE

    mHashMap.put(currLocationMarker, 0);

    mGoogleMap.moveCamera(CameraUpdateFactory.newLatLng(latLng));
    mGoogleMap.animateCamera(CameraUpdateFactory.zoomTo(11));
    mGoogleMap.setMyLocationEnabled(true);

    getMapPin();

    //If you only need one location, unregister the listener
    LocationServices.FusedLocationApi.removeLocationUpdates(mGoogleApiClient, this);
}
于 2017-01-20T18:40:21.793 回答