我提出的解决方案与发布的答案略有不同,所以我认为最好写一个明确的答案。
关键是子类化QAbstractItemModel
(或者更准确地说..ListModel
,这样您就不必处理 C++和QML 中的行/列)。
这样做时,您不仅可以简单地将模型设置为属性
QQuickItem *mainform = view->rootObject();
QQuickItem *grid = (QQuickItem *)mainform->findChild<QObject*>("GridView object name");
ItemModel itemmodel;
itemmodel.setItems(objlist):
QQmlProperty::write(grid, "model", QVariant::fromValue(&itemmodel));
每当对模型进行更改时,它也会通知 QML,例如删除项目。(不过,您必须正确处理更改,请参见removeRows()
示例)
这是我的项目模型:
// itemmodel.h
#include <QAbstractListModel>
#include <item.h>
class ItemModel : public QAbstractListModel
{
Q_OBJECT
public:
explicit ItemModel(QObject *parent = 0);
QHash<int, QByteArray> roleNames() const;
public slots:
void setItems(QList<Item *> items);
QVariant data(const QModelIndex &index, int role = Qt::DisplayRole) const;
int rowCount(const QModelIndex & parent = QModelIndex()) const;
bool removeRows(int row, int count, const QModelIndex &parent = QModelIndex());
private:
QList<Item *> items;
};
// itemmodel.cpp
#include "itemmodel.h"
ItemModel::ItemModel(QObject *parent) : QAbstractListModel(parent)
{
}
// Column Names have to match all the Q_PROPERTYs defined in Item
const char* COLUMN_NAMES[] = {
"property1",
"property2",
"...",
NULL
};
QHash<int, QByteArray> makeRoleNames()
{
int idx = 0;
QHash<int, QByteArray> roleNames;
while(COLUMN_NAMES[idx])
roleNames[Qt::UserRole + idx + 1] = COLUMN_NAMES[idx++];
return roleNames;
}
QHash<int, QByteArray> ItemModel::roleNames() const
{
static const QHash<int, QByteArray> roleNames = makeRoleNames();
return roleNames;
}
void ItemModel::setItems(QList<Item *> items)
{
this->items = items;
}
int ItemModel::rowCount(const QModelIndex & /* parent */) const
{
return items.count();
}
bool ItemModel::removeRows(int row, int count, const QModelIndex &parent)
{
Q_UNUSED(parent);
beginRemoveRows(QModelIndex(), row, row + count - 1);
while (count--) delete items.takeAt(row);
// example for custom deletion:
// items.takeAt(row)->removeFromRoot();
endRemoveRows();
return true;
}
QVariant ItemModel::data(const QModelIndex &index, int role) const {
if (!index.isValid())
return QVariant();
if (index.row() >= items.size() || index.row() < 0)
return QVariant();
if (role == Qt::DisplayRole) {
return QVariant::fromValue(this->items.at(index.row()));
}
if (role > Qt::UserRole)
return this->items.at(index.row())->property(makeRoleNames()[role]);
}
资料来源:
- [1]关于为 QML 创建 QAbstractItemModel 子类的 Qt 文档页面
- [2] QAbstractItemModel 参考
- [3] QAbstractItemModel 子类化指南
- [4]带有 QAbstractListModel 子类的论坛帖子
- [5] QAbstractItemModel 的工作(几乎,
data()
略有改动)实现,我从中获取了角色名称函数