0

我是编写 Java 客户端代码来调用 RestFul Web 服务的新手。这些 Web 服务使用 OAuth2.0 安全性。我有客户端 ID 和密钥,但无法通过 Java 程序调用。我应该如何从中获取访问令牌并将此令牌进一步用于 Web 服务 API 调用。这是我尝试的方法:

private static void authorizationProcess() throws ClientProtocolException, IOException {

    DefaultHttpClient httpClient = new DefaultHttpClient();

    HttpContext context = new BasicHttpContext();
    HttpGet httpGet = new HttpGet("https://www.ustream.tv/oauth2/authorize?response_type=token&client_id=671c71f800c17f1d57f10eebeba2f42d230143cddji8&redirect_uri=www.ustream.tv");
    try {
        HttpResponse httpResponse = httpClient.execute(httpGet, context);
        System.out.println("Response status: " + httpResponse.getStatusLine());
        HttpRequest req = (HttpRequest) context.getAttribute(
                ExecutionContext.HTTP_REQUEST);
        System.out.println("Last request URI: " + req.getRequestLine());
        RedirectLocations redirectLocations = (RedirectLocations) context.getAttribute(
                DefaultRedirectStrategy.REDIRECT_LOCATIONS);
        if (redirectLocations != null) {
            System.out.println("All intermediate redirects: " + redirectLocations.getAll());
        }
        EntityUtils.consume(httpResponse.getEntity());
    } finally {
        httpGet.releaseConnection();
    }
}
}

它给出了错误的请求错误消息:

Response status: HTTP/1.1 400 Bad Request
Last request URI: GET /oauth2/authorize?response_type=token&client_id=671c71f800c17f1d57f10eebeba2f42d230143cddji8&    redirect_uri=www.ustream.tv HTTP/1.1
4

2 回答 2

0

您正在尝试在 Java 代码中执行授权代码授权,但该授权类型是为真正的浏览器交互而设计的。您应该查看授权类型,例如资源所有者密码凭据或客户端凭据,它们都可以与非基于浏览器的客户端一起使用。

于 2016-09-01T15:41:20.690 回答
0

我无法对 Hans Z. 的回答发表评论,但我认为这实际上是对隐式授权的授权请求(response_type=token已使用,详情请点击此处)。例如,它可能是 Android 客户端。某些 API 需要httphttpsredirect_uri您的示例中缺少的 。您可以试一试(请记住百分比编码)..

于 2016-09-02T09:58:52.400 回答