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请帮助我无法在 medoo 中获取最后插入的 ID

下面是我的代码:

 <?php
        header('Access-Control-Allow-Origin: *');
        header('Access-Control-Allow-Methods: GET,OPTIONS,POST,PUT,DELETE');
        header("Access-Control-Allow-Headers: Origin, X-Requested-With, Content-Type, Accept");
        require 'vendor/autoload.php';
        $app = new\Slim\Slim();
        $app->container->singleton('db',function () use ($app) {
            return new medoo([
            'database_type' =>'pgsql',
            'database_name' =>'emergency',
            'server'=>'localhost',
            'username' =>'postgres',
            'password' => 'root',
            'charset' => 'utf8',
            'option' =>[
                PDO::ATTR_CASE=>PDO::CASE_NATURAL
            ]
            ]);
        });
$app->db->post('/getinfo',function()
{
$body = $app->request->post();
 $app->db->insert("emergencymessages", [

            "message" =>$body["msg"],
            "createdby"=>$createdby
            ]); 
});

现在我想获取紧急消息表的最后插入 id 我怎么能得到它?

4

1 回答 1

1

根据文档(http://medoo.in/api/insert),该insert函数返回最后一个插入 ID。

$last_insert_id = $app->db->insert("emergencymessages", [
              "message" =>$body["msg"],
              "createdby"=>$createdby
            ]); 

编辑:

您可以尝试lastInsertId();直接调用 medoo 的pdo对象:

$last_insert_id = $app->db->pdo->lastInsertId();
于 2016-06-23T06:02:06.077 回答