3

我正在尝试使程序仅使用 SysLogHandler 实例进行日志记录,而不使用其他处理程序。我希望它不会记录到任何文件或标准输出。

    self.logger = logging.getLogger(self.name)

    syslog_handler = logging.handlers.SysLogHandler(
        socktype=socket.AF_UNIX,
        address='/dev/log',
        facility=logging.handlers.SysLogHandler.LOG_LOCAL4,
    )

    # Check if there is a handler attached
    if len(self.logger.handlers) > 0:

        # If there is a handler attached
        # ensure it is a SysLogHandler instance

        handler = self.logger.handlers[0]
        if not (handler.__class__ == logging.handlers.SysLogHandler):
            # If is was something else but a SysLogHandler instance,
            # remove it and attach the syslog_handler

            self.logger.handlers = []
            self.logger.addHandler(syslog_handler)
    else:
        # If no handlers attached,
        # attach syslog_handler

        self.logger.handlers = []
        self.logger.addHandler(syslog_handler)

但是通过这种设置,它在运行时会继续向标准输出吐出行python srcipt.py

4

1 回答 1

8

你有不同的方法来做到这一点:

-将 logger.propagate 设置为 false。

并将其交给您的记录器。

logging.StreamHandler(stream=None)
于 2016-05-26T12:32:00.733 回答