php - Medoo MySQL没有读取变量

Question

我正在使用 Medoo MySQL 框架，但在 WHERE 语句中使用 IN 时遇到了这个问题：

$test = '1,2,3,4';

$count = $database->count("products", [
    "AND" => [
        "category_id" => $category['id'],
        "id" => [$test]
    ]
]);

计数结果应该是 4，但我得到 1。但是：

$count = $database->count("products", [
    "AND" => [
        "category_id" => $category['id'],
        "id" => [1,2,3,4]
    ]
]);

给了我 4 的正确结果。有什么想法吗？提前致谢！

Answer 1

尝试这个...

$test = array(1,2,3,4);

$count = $database->count("products", [
    "AND" => [
        "category_id" => $category['id'],
        "id" => $test // variable without []
    ]
]);

Answer 2

以下解决方案已在此处发布： https ://github.com/catfan/Medoo/issues/637

$values = '2,123,234,54';

$database->select("account", "user_name", [
    "OR" => [
        "user_id" => explode(',',$values)
    ]
]);

Answer 3

$test = '1,2,3,4';是一个字符串。要将其转换为数组，您需要使用：

$test = explode(',', '1,2,3,4');

$count = $database->count("products", [
    "AND" => [
        "category_id" => $category['id'],
        "id" => $test
    ]
]);