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我试图在 SpriteKit 游戏中产生一波又一波的敌人。我认为这段代码会起作用。如何runAllWaves()在调用下一波之前等待每一波完成？（我意识到如果所有其他方法都失败了，我可以人为地增加 waveWait 时间，从每个波的开始而不是结束计数）

import SpriteKit

let waveWait =  [5, 10, 10] // pause before each wave
let waveCount = [10, 20, 50] // num. of enemies in each wave
let waveDelay = [3, 2, 1] // pause before each enemy spawns
let waveHealth = [1, 2, 3] // enemy health for each wave

var index:Int = 0

var spawn = SKAction()
var delay = SKAction()
var spawndelay = SKAction()
var repeatspawndelay = SKAction()
var wait = SKAction()
var dowave = SKAction()

var doAllWaves = SKAction()


class GameScene: SKScene {

    override func didMoveToView(view: SKView) {

        print("begin!")

         runAllWaves()
    }

    func runWave(index:Int){

        spawn = SKAction.runBlock({ self.spawnEnemy(index) })
        delay = SKAction.waitForDuration(NSTimeInterval(waveDelay[index]))
        spawndelay = SKAction.sequence([spawn, delay])
        repeatspawndelay = SKAction.repeatAction( spawndelay , count: waveCount[index])

        self.runAction(repeatspawndelay)

    }

    func runAllWaves(){
        runAction(SKAction.sequence([
            SKAction.waitForDuration(NSTimeInterval(waveWait[index])),
            SKAction.runBlock({ self.runWave(index)  }) ]),
            completion: {
                index += 1
                if index < 3 { self.runAllWaves() }})
    }

    func spawnEnemy(index:Int){ print("spawn enemy with health: " + String(waveHealth[index])) }

}
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1 回答 1

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为什么不实现一个runNextWave功能并在末尾调用它runWave？您有定义每个波的属性的数组；如果数组中的第一个元素确定了波的属性，那么在runWave您可以删除这些条目并在结束时再次runWave调用runWave，直到数组为空或满足其他条件。

于 2016-03-26T12:58:31.487 回答