6

我试图用空字符串替换字符串中的所有非单词字符,期望空格,并将所有多个空格放在一起作为一个空格。

以下代码执行此操作。

$cleanedString = preg_replace('/[^\w]/', ' ', $name);  
$cleanedString = preg_replace('/\s+/', ' ', $cleanedString);

但是当我尝试使用 mb_ereg_replace 时,什么也没有发生。

$cleanedString = mb_ereg_replace('/[^\w]/', ' ', $name);  
$cleanedString = mb_ereg_replace('/\s+/', ' ', $cleanedString);

$cleanedString 与上述情况下的 if $name 相同。我究竟做错了什么?

4

3 回答 3

11

mb_ereg_replace不使用分隔符。您之前可能还必须指定编码,也可能不必指定编码。

mb_regex_encoding("UTF-8");
//regex could also be \W
$cleanedString = mb_ereg_replace('[^\w]', ' ', $name);
$cleanedString = mb_ereg_replace('\s+', ' ', $cleanedString);
于 2010-08-29T13:16:51.337 回答
-1
function create_slug_html($string, $ext='.html'){     
   $replace = '-';         
   $string=strtolower($string);     
   $string=trim($string);

    mb_regex_encoding("UTF-8");
    //regex could also be \W
    $string= mb_ereg_replace('[^\w]', ' ', $string);
    $string= mb_ereg_replace('\s+', ' ', $string);

   //remove query string     
   if(preg_match("#^http(s)?://[a-z0-9-_.]+\.[a-z]{2,4}#i",$string)){         
         $parsed_url = parse_url($string);         
         $string = $parsed_url['host'].' '.$parsed_url['path'];         
         //if want to add scheme eg. http, https than uncomment next line         
         //$string = $parsed_url['scheme'].' '.$string;     
   }      
   //replace / and . with white space     
   $string = preg_replace("/[\/\.]/", " ", $string);   

   // $string = preg_replace("/[^a-z0-9_\s-]/", "", $string);  

   //remove multiple dashes or whitespaces     
   $string = preg_replace("/[\s-]+/", " ", $string);   

   //convert whitespaces and underscore to $replace     
   $string = preg_replace("/[\s_]/", $replace, $string);     
   //limit the slug size     
   $string = substr($string, 0, 200);     
   //slug is generated     
   return ($ext) ? $string.$ext : $string; 

}

请检查是否可以并支持英文和unicode

于 2016-07-24T09:25:36.383 回答
-5

输入不是多字节,因此mb函数失败。

于 2010-08-29T12:12:04.563 回答