pythonxy - 如何使用 NumPy 从 Python 中特定位置的数组中删除元素？

Question

heads = 0我需要用和模拟掷硬币tails = 1。并且每次生成一个介于 1 和 0 之间的随机数时，都需要在数组中递增和更新正面或反面。下面是我的代码：

import numpy, random

flips = numpy.array([0,0])
coin = heads = tails = 0
for i in range(10):
  coin = random.randint(0,1)
  if coin == 0:
      heads += 1

(Now at this point, I want to update the second position of the array because that represents heads, how would I do that?  And the same for the first position, with tails).

请帮忙 ：）

Answer 1

你可以使用流行音乐

数组 = [1,2,3,4]

数组.pop(1)

现在数组是 [1,3,4]

默认情况下，不带任何参数的 pop 会删除最后一项

数组 = [1,2,3,4] 数组.pop()

现在数组是 [1,2,3]

Answer 2

这不是诀窍吗？

import numpy, random

flips = numpy.array([0,0])

for i in range(10):
    flips[random.randint(0,1)] += 1