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我对 C 编程完全陌生，我正在尝试创建一个Word Search。

我有一个单词列表，其中只有 4 个是随机挑选的。这 4 个单词将在水平、垂直或对角的网格中打印，但是我只能让它们水平打印。我还必须补充一点，我不知道这段代码是如何工作的，所以如果有足够好心的人真的可以帮助我，我真的很感激。那么任何人都可以帮助我在正确的方向上创建垂直和对角对齐的随机单词吗？ http://imgur.com/VSrXf4C

void putHorizzontalWord(char word[10])
{
    int rRow, rCol , ok , i;

    do
    {

        rRow = rand() % 10;
        rCol = rand() % 10;

        ok = 1;
        if(rCol + strlen(word) < 10)
        {
            for(i = 0;i < strlen(word);i++)
            {
                if(puzzle[rRow][rCol + i] == ' ' || 
                    puzzle[rRow][rCol + i] == word[i])
                {
                    puzzle[rRow][rCol + i] = word[i];
                }
                else
                {
                    ok = 0;
                }
            }
        }
        else
        {
            ok = 0;
        }
    }
    while(ok == 0);
}
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1 回答 1

0

以下是一些注释，旨在向您解释该代码的作用：

// This function takes a string as input then puts that string
// at a random "open" location in a 2D grid (puzzle) in an
// horizontal manner
//
// This function expects the size of the string to be at most = 10

void putHorizontalWord(char word[10])
{
    int rRow, rCol , ok , i;

    do
    {
        // Randomly select a location
        rRow = rand() % 10;
        rCol = rand() % 10;

        // For now, assume that this location is "ok", i.e. is open
        ok = 1;

        // Check that the word fits inside the grid from (rRow, rCol)
        if(rCol + strlen(word) < 10)
        {
            // If it does, then try to put the word at this location
            // Thus, we need to process the word character by character
            for(i = 0;i < strlen(word);i++)
            {
                // We are inside the for loop
                // The current character to process is word[i]
                // And the current cell to fill is (rRow, rCol + i)
                //
                // If current cell is empty || is same as the current character
                // then this cell is "open" i.e. we can use it
                if(puzzle[rRow][rCol + i] == ' ' || 
                    puzzle[rRow][rCol + i] == word[i])
                {
                    puzzle[rRow][rCol + i] = word[i];
                }
                else
                {
                    // The cell is not open
                    // => (rRow, rCol) is not "ok"
                    ok = 0;
                }
            }
        }
        else
        {
            // word not fits inside the grid from the location
            // => (rRow, rCol) is not "ok"
            ok = 0;
        }
    }
    while(ok == 0); // Exit loop while not found a good location
}

如果您已经理解，那么您现在可以修改它以编写您的垂直和对角线版本。如果您仍然不明白，请告诉我还有什么不清楚的地方。

于 2016-01-05T21:50:30.337 回答