1

在脚本中使用 adhoc nlapiSearchRecord 时，例如：

        var filters = new Array();
        var columns = new Array();
                filters[0] = new nlobjSearchFilter('isinactive', null, 'is', 'F' );
                filters[1] = new nlobjSearchFilter('vendorcost', null, 'greaterthan', 0);
                filters[2] = new nlobjSearchFilter('internalid', 'vendor', 'anyof', vendorid );
                columns[0] = new nlobjSearchColumn('itemid');
                columns[1] = new nlobjSearchColumn('entityid', 'vendor');
                columns[2] = new nlobjSearchColumn('vendorcode');
                columns[3] = new nlobjSearchColumn('formulanumeric'); 
                    columns[3].setFormula('{vendorcost}');
                columns[4] = new nlobjSearchColumn('vendorpricecurrency');
                columns[5] = new nlobjSearchColumn('isinactive');
                columns[6] = new nlobjSearchColumn('vendor');
                columns[7] = new nlobjSearchColumn('averagecost');
                columns[8] = new nlobjSearchColumn('lastpurchaseprice');
                columns[9] = new nlobjSearchColumn('custitem_costrepl');
                var searchresults = nlapiSearchRecord('item', null, filters, columns );

如何检索第 3 列中公式的值？

我试过了searchresults.getValue(column[3]))，searchresults.getValue(3))但都失败了。

原因是我们的一些vendorcost值是 4 或 5 位小数，但普通搜索返回的最小数精度是 3。

4

2 回答 2

2 
var filters = new Array();
filters[0] = new nlobjSearchFilter('isinactive', null, 'is', 'F');
filters[1] = new nlobjSearchFilter('vendorcost', null, 'greaterthan', 0);
filters[2] = new nlobjSearchFilter('internalid', 'vendor', 'anyof', vendorid);

var columns = new Array();
columns[0] = new nlobjSearchColumn('itemid');
columns[1] = new nlobjSearchColumn('entityid', 'vendor');
columns[2] = new nlobjSearchColumn('vendorcode');
columns[3] = new nlobjSearchColumn('formulanumeric').setFormula('{vendorcost}'); // you can use formula inline
columns[4] = new nlobjSearchColumn('vendorpricecurrency');
columns[5] = new nlobjSearchColumn('isinactive');
columns[6] = new nlobjSearchColumn('vendor');
columns[7] = new nlobjSearchColumn('averagecost');
columns[8] = new nlobjSearchColumn('lastpurchaseprice');
columns[9] = new nlobjSearchColumn('custitem_costrepl');
var searchresults = nlapiSearchRecord('item', null, filters, columns);

for (var i = 0; searchresults != null && i < searchresults.length; i++) {
    var vendorcost = searchresults[i].getValue(columns[3]);  // gives you the formula field value
}
于 2015-12-31T12:42:40.750 回答
2

您忽略了 searchResults 是一个数组的事实

并且有多种方式：

选项#1 //始终有效

searchresults[INDEX].getValue(searchresults[INDEX].getAllColumns()[3]);

Option#2 // 始终有效 - 与您尝试的相同，但是您错过了数组

searchresults[i].getValue(columns[3]);

选项#3 //仅在您有一个数字公式时使用

searchresults[INDEX].getValue('formulanumeric');
于 2015-12-31T12:50:53.900 回答