3

我不知道如何找到这些词.. 示例我有这个文本...

The other day I went to the <location> and bought some <plural-noun> . Afterwards, I went to <location> , but it was very <adjective> so I left quickly and went to <location> .

<当我在谷歌上搜索时，我不知道要搜索什么原因>，它将被忽略。需要帮助如何获取此字符串。

所以我会得到<location>, <plural-noun>, <location>, <adjective>,<location>

我必须使用charAt()方法。我的尝试：

String string = this.fileName;
for(int i = 0; i < string.length(); i++)
                if((string.charAt(i) == '<') && (string.charAt(i) == '>'))
                    System.println(""); //<-------- IM STUCK HERE

不知道……快两天没睡了。

我当前但最后一个问题...如何删除<和>显示的每个单词？

String string = this.template;
        Pattern pattern = Pattern.compile("<.*?>");
        Matcher matcher = pattern.matcher(string);

        List<String> listMatches = new ArrayList<String>();

        while(matcher.find()) {
            listMatches.add(matcher.group());
        }
        // System.out.println(listMatches.size());
        int indexNumber = 1;
         for(String s : listMatches) {
             System.out.println(Integer.toString(indexNumber) + ". " + s);
             indexNumber++;
         }
4

3 回答 3

5

你可以使用Pattern和Matcher类。

  1. 搜索正则表达式模式<.*?>。
  2. 使用 Matcher 查找模式。
于 2015-10-04T06:05:51.993 回答
2

这里确实有两个问题，所以我只回答最后一个；当你有<text>你想要的，去这样的：

String text = "<the_text_you_want>";

text.replace("<","").replace(">","").replace("-"," ");

这将摆脱分隔符。

于 2015-10-04T07:08:25.997 回答
1

阅读整行并将其存储在String line. 然后，使用：

String line = "The other day I went to the <location> and bought some <plural-noun> . Afterwards, I went to <location> , but it was very <adjective> so I left quickly and went to <location> ."; 

boolean found = false;
String data[] = new String[20];
int counter = 0;

Arrays.fill(data, "");

for(int i = 0; i < line.length() && counter < 20; i++) {
    if(line.charAt(i) == '<')
        found = true;
    else if(line.charAt(i) == '>' && found) {
        found = false;
        counter++;
    }
    else if(found) {
        data[counter] += line.charAt(i);
    }
}

for(int i = 0; i < counter; i++)
    System.out.println("Scanned data #" + (i + 1) + " = " + data[i]);
于 2015-10-04T06:23:43.647 回答