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I have a column which type is SPGroup in a list. I want to get items via SharePoint REST API, and I only need the items which SPGroup contains the current user. So what's the URL? Thank you for your advice!

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2 回答 2

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您可以$expand在 REST 查询中使用该参数在查询中包含相关的数据实体,但由于 SharePoint REST 服务实现了 OData 协议,因此该$filter方法只能在顶级项目上调用,因此无法在扩展领域。

根据您的列表包含多少项目,我建议您尝试在当前用户以外的其他内容上对其进行过滤,或者获取所有内容并在代码中过滤结果。

REST 查询看起来像这样:

http://sp/_api/web/lists/getbytitle('MyList')/items?$select=Id,Title,Members/Id&$expand=Members哪里MembersSPGroup要扩展的。

在返回的每个项目中,你会得到类似的东西

<content type="application/xml">
   <m:properties>
      <d:Id m:type="Edm.Int32">60</d:Id>
   </m:properties>
</content>

Id成员的价值。由此,您应该能够编写一些自定义代码来仅过滤掉包含当前登录用户的项目。

于 2015-09-07T13:53:51.167 回答
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您仍然可以使用优质的老式 SOAP 来做您想做的事情,而不会让人头疼。我使用此方法将任务分配给用户帐户或他们所属的组。

function getAssignedToMe(){

    var viewFields = '<ViewFields><FieldRef Name="ID" /><FieldRef Name="Title" /><FieldRef Name="Created" /><FieldRef Name="FileRef" />'
        +'<FieldRef Name="AssignedTo" /><FieldRef Name="Status" /></ViewFields>';   

    // filter by AssignedTo is current user ID or assigned to the current user's group;
    var camlQuery = '' + 
        '<Query>' + 
            '<Where>' + 
                '<And>' + 
                    '<Or>' + 
                        '<Membership Type="CurrentUserGroups"><FieldRef Name="AssignedTo"/></Membership>' + 
                        '<Eq><FieldRef Name="AssignedTo"/><Value Type="Integer"><UserID/></Value></Eq>' + 
                    '</Or>' + 
                    '<And>' + 
                        '<Neq><FieldRef Name="Status"/><Value Type="Text">Completed</Value></Neq>' + 
                        '<Geq><FieldRef Name="Created" /><Value Type="DateTime"><Today OffsetDays="-60" /></Value></Geq>' + 
                    '</And>' + 
                '</And>' + 
            '</Where>' + 
            '<OrderBy><FieldRef Name="Created" Ascending="TRUE"/></OrderBy>' +
        '</Query>';

    getListItems('/mysite', 'Tasks', viewFields, camlQuery, callback, 50);

    // transform the returned XML to JSON
    function callback(xmlDoc){
        var data = [];
        $(xmlDoc).find('*').filter(function () {
            return this.nodeName.toLowerCase() == 'z:row';
        }).each(function (i, el) {
            // do something with the data
            var id = parseInt($(el).attr('ows_ID'));
            data.push({
                Id: id
            });
            /* ... */
        });
    };

 };

 function getListItems(siteUrl, listName, viewFields, query, callback, rowLimit) {
    if (rowLimit === void 0) { rowLimit = 25; }

    var packet = '<?xml version="1.0" encoding="utf-8"?>' +
        '<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">' +
        '<soap:Body>' +
        '<GetListItems xmlns="http://schemas.microsoft.com/sharepoint/soap/">' +
        '<listName>' + listName + '</listName>' +
        '<query>' + query + '</query>' +
        '<viewFields>' + viewFields + '</viewFields>' +
        '<rowLimit>' + rowLimit + '</rowLimit>' +
        '</GetListItems>' +
        '</soap:Body>' +
        '</soap:Envelope>';

    var $jqXhr = $.ajax({
        url: siteUrl + '/_vti_bin/lists.asmx',
        type: 'POST',
        dataType: 'xml',
        data: packet,
        headers: {
            "SOAPAction": "http://schemas.microsoft.com/sharepoint/soap/GetListItems",
            "Content-Type": "text/xml; charset=utf-8"
        }
    }).done(function (xmlDoc, status, error) {
        callback(xmlDoc);
    }).fail(function (jqXhr, status, error) {
        callback(null, status + ': ' + error);
    });
};
于 2017-01-19T20:29:49.647 回答