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该代码从卡中抓取了一个单独的事件，但我不断收到此错误：

C:\Python27\python.exe C:/Users/James/PycharmProjects/scraperscrapy /scrapy.py Traceback（最近一次调用最后）：文件“C:/Users/James/PycharmProjects/scraperscrapy/scrapy.py”，第 31 行, 在 writer.writerow(c) ValueError: I/O operation on closed file

我正在使用 pyCharm。

以退出代码 1 完成的过程 Python 即时创建 csv 文件，但我也尝试在项目中创建一个 csv 文件，但仍然收到相同的消息。我认为问题可能出在第 31 行 zip 之后的字符串中。任何帮助表示赞赏。

import csv
from urllib import urlopen
from bs4 import BeautifulSoup

html = urlopen("http://www.gbgb.org.uk/resultsRace.aspx?id=1793467")
bsObj = BeautifulSoup(html)

one = bsObj.findAll("li", {"class": "first essential fin"})
two = bsObj.findAll("li", {"class": "essential greyhound"})

three = bsObj.findAll("li", {"class": "timeDistance"})
four = bsObj.findAll("li", {"class": "trap"})
five = bsObj.findAll("li", {"class": "sp"})
six = bsObj.findAll("li", {"class": "timeSec"})
seven = bsObj.findAll("li", {"class": "essential trainer"})
eight = bsObj.findAll("li", {"class": "first essential comment"})

firstessentialfin = [a.getText().strip() for a in one]
essentialgreyhound = [b.getText().strip() for b in two]
timeDistance = [c.getText().strip() for c in three]
trap = [d.getText().strip() for d in four]
sp = [e.getText().strip() for e in five]
timeSec = [f.getText().strip() for f in six]
essentialtrainer = [g.getText().strip() for g in seven]
firstessentialcomment = [h.getText().strip() for h in eight]

with open('dogfile.csv', 'wb') as csvfile:
    writer = csv.writer(csvfile, delimiter=",")
for c in zip(firstessentialfin, essentialgreyhound, timeDistance,    trap,sp, timeSec, essentialtrainer,
         firstessentialcomment):
    writer.writerow(c)
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1 回答 1

2

问题在于缩进。将 for 循环移动到with上下文管理器主体下：

with open('dogfile.csv', 'wb') as csvfile:
    writer = csv.writer(csvfile, delimiter=",")
    for c in zip(firstessentialfin, essentialgreyhound, timeDistance,    trap,sp, timeSec, essentialtrainer, firstessentialcomment):
        writer.writerow(c)
于 2015-09-01T17:42:52.943 回答