0

这是我的代码:-

package javaapplication;

import java.util.Scanner;

public class perfect02 {

    public static void main(String args[]) {
        int i = 1, sum = 0;

        System.out.println("Enter maximum range : ");
        Scanner kb = new Scanner(System.in);

        int a = kb.nextInt();
        System.out.println("Enter minimum range : ");

        Scanner kb2 = new Scanner(System.in);
        int b = kb2.nextInt();

        System.out.println("perfect number in the given range are :");
        for (int n = b; n <= a; n++) {
            while (i < n) {
                if (n % i == 0) {
                    sum = sum + i;
                }
                i++;
            }
            if (sum == n)
                System.out.println(+n + " ");
        }
    }
}

为什么程序不打印完美数字?

我已经检查了很多次代码,但我找不到解决方案。请告诉我我的代码出了什么问题。提前致谢

任何帮助,将不胜感激 ....

4

1 回答 1

2

在这里,我研究了完美的数字生成并为您修复了它!

public static void main(String args[]) {
    Scanner kb = new Scanner(System.in);
    System.out.println("Enter minimum range : ");
    int b = kb.nextInt();
    System.out.println("Enter maximum range : ");
    int a = kb.nextInt();
    kb.close();
    System.out.println("Perfect number in the given range are :");
    for (int n = b; n <= a; n++) {
        int sum = 0;
        int i = 1;
        while (i < n) {
            if (n % i == 0)
                sum = sum + i;
            i++;
        }
        if (sum == n)
            System.out.println(n + " is perfect");

    }
}

您应该已经在 for 循环中声明了 sum 和 i 变量,因此它们将为每个数字重置!

于 2015-07-24T08:17:12.987 回答