0

我在我的一个 cakePHP 2.6 项目(和 DT 1.10.6)中使用了 tigrang/cakephp-datatable 。到目前为止,在插件作者的帮助下,我已经能够成功实现该插件。该插件非常好,我想保留它。

现在,我正在尝试使用vedmack/YADCF插件以及我现有的数据表来实现(尤其是)列过滤功能,因为我发现官方 DT 上的示例非常混乱和有限。初始化 YADCF 时不断出错:

TypeError: oTable.settings is not a function
var instance = oTable.settings()[0].oInstance,

有没有办法让两个插件一起工作?有没有人试过这个?

下面是我使用 cakephp-datatable 的 DT JS:

$('.dataTable').each(function() {
    var table = $(this);
    var model = table.attr('data-config');
    var settings = dataTableSettings[model];
    settings['dom'] = 'lrtip';
    settings['stateSave'] = true;
    settings['stateSaveCallback'] = function (settings, data) {
                $.ajax( {...});
            };
    settings['stateLoadCallback'] = function (settings) {
            ...
            };
    table.dataTable(settings);
});

在上面的代码之后,我尝试了类似的方法和其他一些尝试以使 YADCF 工作,但我总是遇到同样的错误:

var table = $('.dataTable');
yadcf.init(table, [
            {column_number: 0, filter_type: "text", filter_reset_button_text: false, filter_delay:500},
            ...,
            {column_number: 4, filter_type: "select", filter_default_label: "Select", filter_reset_button_text: false, filter_delay:500},
            {column_number: 5, filter_type: "range_number", filter_reset_button_text: false, filter_delay:500},
            ...,
        ]);

我已经在没有其他插件的情况下尝试了这个 YADCF 代码,它可以完美运行。所以,我需要帮助修改代码以使用其他插件实现。

我也试过这个(因为 DT 是使用dataTable()小写“d”初始化的)但没有奏效:

$('.dataTable').each(function() {
...
...
table.dataTable(settings)
        .yadcf([
                {column_number: 0, ...},
                ...
            ]);
});

PS:我也在第一个插件的github上问过这个问题,但我希望yadcf的作者或有经验的人可以在这里帮助我。

4

1 回答 1

1

尝试以下(删除循环/this用法)

var table;
var model = table.attr('data-config');
var settings = dataTableSettings[model];
settings['dom'] = 'lrtip';
settings['stateSave'] = true;
settings['stateSaveCallback'] = function (settings, data) {
            // Send an Ajax request to the server with the state object
            $.ajax( {
                "url": "/cake/Users/save_state",
                "data": data,
                "dataType": "json",
                "type": "POST",
                "success": function () {
                    console.log("ca");
                },
            });
        };
settings['stateLoadCallback'] = function (settings) {
        var o;

        // Send an Ajax request to the server to get the data. Note that
        // this is a synchronous request since the data is expected back from the
        // function
            $.ajax( {
                "url": "/cake/Users/get_state",
                "async": false,
                "dataType": "json",
                "success": function (json) {
                o = json;
                },
            });
        return o;
        };
table = $('.dataTable').DataTable(settings);

yadcf.init(table, [
    {column_number: 0, filter_type: "text", filter_reset_button_text: false, filter_delay:500},
    {column_number: 1, filter_type: "text", filter_reset_button_text: false, filter_delay:500},
    {column_number: 2, filter_type: "text", filter_reset_button_text: false, filter_delay:500},
    {column_number: 3, filter_type: "text", filter_reset_button_text: false, filter_delay:500},
    {column_number: 4, filter_type: "select", filter_default_label: "Select", filter_reset_button_text: false, filter_delay:500},
    {column_number: 5, filter_type: "range_number", filter_reset_button_text: false, filter_delay:500},
    {column_number: 6, filter_type: "select", filter_default_label: "Select", filter_reset_button_text: false, filter_delay:500},
]);

或者您可以将当前代码修改为

$('.dataTable').DataTable(settings); --> return $('.dataTable').DataTable(settings);

dtable('.dataTable'); --> var oTable = dtable('.dataTable');

于 2015-06-25T11:23:37.863 回答