0
def remove_duplicates(strng):
    """
    Returns a string which is the same as the argument except only the
    first occurrence of each letter is present.  Upper and lower case
    letters are treated as different.  Only duplicate letters are removed,
    other characters such as spaces or numbers are not changed. 

    >>> remove_duplicates('apple')
    'aple'
    >>> remove_duplicates('Mississippi')
    'Misp'
    >>> remove_duplicates('The quick brown fox jumps over the lazy dog')
    'The quick brown fx jmps v t lazy dg'
    >>> remove_duplicates('121 balloons 2 u')
    '121 balons 2 u'
    """
    s = strng.split()
    return strng.replace(s[0],"")

编写一个函数来消除重复的字母,但到目前为止已经玩了一个小时,什么也得不到。帮助将不胜感激,谢谢。

4

3 回答 3

3

不是最有效但最直接的方法是:

>>> s = 'The quick brown fox jumps over the lazy dog'
>>> import string
>>> n = ''
>>> for i in s:
        if i not in string.ascii_letters:
            n += i
        elif i not in n:
            n += i


>>> n
'The quick brown fx jmps v t lazy dg'
于 2010-05-19T12:01:20.710 回答
2

使用列表理解:

>>> from string import whitespace, digits
>>> s = 'The quick brown fox jumps over the lazy dog'
>>> ''.join([c for i, c in enumerate(s) if c in whitespace+digits \
                                                      or not c in s[:i]])
于 2010-05-19T20:22:27.567 回答
0

尝试这个 ...

def remove_duplicates(s):
    result = ""
    dic = {}
    for i in s:
        if i not in dic:
            result+=i
            if ord(i.lower()) >= ord('a') and ord(i.lower()) <= ord('z'):
                dic[i] = 1
    return result
于 2010-05-19T12:07:21.210 回答