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我正在尝试使用 ActiveDataProvider 作为我的 ActiveDataForm 的源。但是我无法访问这些信息。不是来自视图或控制器。diseaseList + ListView 是如何工作的。

我似乎无法弄清楚我哪里出错了。即使我得了这样的病：

$disease = new Disease();
$disease = Disease::find()->where(['id'=>1]);

我无法访问数据。只有当我在控制器中启动新疾病时，我才能让 ActiveForm 正常工作。

控制器：

public function actionIndex($id = 1)
{
    $disease = new ActiveDataProvider([
        'query' => Disease::find()
        ->where(['id'=>$id]),
            'pagination' =>  [
                'pageSize' => 1,
            ]
        ]);
    
    $diseaseList = new ActiveDataProvider([
        'query' => Disease::find()->orderBy('LOWER(name)'),
            'pagination' =>  [
                'pageSize' => 20,
            ]
        ]);
    return $this->render('index', ['disease' => $disease, 'diseaseList' => $diseaseList]);
}

在我看来：

<?php 
echo ListView::widget([
'dataProvider' => $diseaseList,
'itemView' => function($diseaseList, $key, $index, $widget)
{
    return 
        Html::a($diseaseList->name,
            Url::toRoute(['disease/index', 'id' => $diseaseList->primaryKey]));
}
]); 
?>

<?php
    $form = ActiveForm::begin([
    'id' => 'disease-form-vertical'
    ]);
    ?>
        <?= $form->field($disease, 'name') ?>
        <?= $form->field($disease, 'description') ?>
        <?= $form->field($disease, 'transmission') ?>
        <?= $form->field($disease, 'actions') ?>
        <?= $form->field($disease, 'report') ?>
        <?= $form->field($disease, 'exclusion') ?>
        <?= $form->field($disease, 'notes') ?>
    <div class="form-group">
        <?= Html::submitButton('Login', ['class' => 'btn btn-primary']) ?>
        <?= Html::resetButton('Reset', ['class' => 'btn btn-default']) ?>
    </div>
    <?php ActiveForm::end(); ?>

这是我收到的错误。 错误

4

1 回答 1

1

这里有一点不对劲，那就是：

$disease = Disease::find()->where(['id'=>1]);

那应该是：

$disease = Disease::find()->where(['id'=>1])->one();

要知道为什么会出现此错误：您正在传递ActiveQuery给您ActiveForm的$disease = Disease::find()->where(['id'=>1])错误。ActiveForm不接受ActiveQuery。

于 2014-11-18T16:40:31.017 回答