-5

我想得到输出：

add reg1,reg2,reg3

我的代码：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void instruction(int binary);
int binaryToDecimal(int n);

int main()
{
    int testBinary = 0001000110100011;
    instruction(testBinary);
}

void instruction(long binary)
{
    char add[4]  = "0001";
    char and[4]  = "0101";
    int binaryRep;

    if(stncmp(add, binary, 4) == 1)
    {
        int reg1;
        int reg2;
        int reg3;
        int temp3;

        binary = binary << 4 ;

        binary = binary << 3 ;
        memcpy(reg1, binary, 3);

        binary = binary << 3 ;
        memcpy(reg2, binary, 3);

        binary = binary <<6;
        memcpy(reg3, binary, 3);

        reg1 = binaryToDecimal(reg1);
        reg2 = binaryToDecimal(reg2);
        reg3 = binaryToDecimal(reg3);

        printf("add r%d, r%d, r%d", reg1,reg2,reg3);
    }

    if(stncmp(and, binary, 4) == 1)
    {
        int reg1;
        int reg2;
        int reg3;
        int temp3;

        binary = binary << 4 ;
        binary = binary << 3 ;
        memcpy(reg1, binary, 3);

        binary = binary << 3 ;
        memcpy(reg2, binary, 3);

        binary = binary <<6;
        memcpy(reg3, binary, 3);

        reg1 = binaryToDecimal(reg1);
        reg2 = binaryToDecimal(reg2);
        reg3 = binaryToDecimal(reg3);

        printf("and r%d, r%d, r%d", reg1,reg2,reg3);


    }

}

int binaryToDecimal(int n) /* Function to convert binary to decimal.*/
{
    int decimal=0, i=0, rem;
    while (n!=0)
    {
        rem = n%10;
        n/=10;
        decimal += rem*pow(2,i);
        ++i;
    }
    return decimal;
}

但是我遇到了类型和 stncmp 的各种错误。错误：警告：从“long”到“int”的隐式转换将值从 68738383881 更改为 18907145 [-Wconstant-conversion]

和

警告：函数 'stncmp' 的隐式声明在 C99 [-Wimplicit-function-declaration] if(stncmp(add, binary, 4) == 1) 中无效

有人可以帮忙吗？

这是 lc3 指令集的副本供参考http://ece224web.groups.et.byu.net/reference/LC3_Instructions.gif

4

1 回答 1

0

您不能使用二进制值初始化变量。以 开头0表示值为octal。开始0x意味着值是hexademical 所以你的初始化可以这样完成：

int testBinary = 0x11A3;

至于stncmp，你不能用它来char*比较int。我想你可能会testbinary为你的情况初始化你这样的：

char testbinary[17] = "0001000110100011";

然后您可以将其与 and.

于 2014-10-20T07:06:21.507 回答