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我想制作一个程序来扫描包含以下内容的文件：

1283

5105

lc3 中两条指令的十六进制代码：

添加 r1,r2,r3

和 r0,r4,r5

我想让我的程序读取这个文件并在屏幕上打印两个相应的指令有人可以告诉我它有什么问题吗

 #include <stdio.h>
 #include <stdbool.h>
 #include <string.h>
     int main(int argc, char *argv[]) {


FILE *file;
char hexString[5];
int dr, sr1, sr2, instruction;
file = fopen(argv[1], "r");

while (fscanf(file, "%d", hexString) != EOF){

    unsigned short int instruction = (unsigned short)strtol(hexString, NULL, 16);

        if (instruction >> 12 == 0b0001){ //op code is ADD

            dr = (instruction >> 9) & 0b111; // turns other bits to zero
            sr1 = (instruction >> 6) & 0b111;
            sr2 = (instruction) & 0b111;

            printf("add r%d r%d r%d", dr, sr1, sr2);

        } else if (instruction >> 12 == 0b0101){//op code is AND

            dr = (instruction >> 9) & 0b111;
            sr1 = (instruction >> 6) & 0b111;
            sr2 = (instruction) & 0b111;

            printf("and r%d r%d r%d", dr, sr1, sr2);
        }
}
fclose(file);
}

当我使用 gcc 编译它时，没有出现编译错误。

这是 lc3 指令集的副本供参考http://ece224web.groups.et.byu.net/reference/LC3_Instructions.gif

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