我不明白如何递归调用我的代码。到目前为止,这是我的代码:
import numpy
B = [[5,5,5,5,5,5,5,5],[6,6,6,6,6,6,6,6],[7,7,7,7,7,7,7,7],[8,8,8,8,8,8,8,8],
[9,9,9,9,9,9,9,9], [10,10,10,10,10,10,10,10],[11,11,11,11,11,11,11,11], [12,12,12,12,12,12,12,12]]
A = [[5,5,5,5,5,5,5,5],[6,6,6,6,6,6,6,6],[7,7,7,7,7,7,7,7],[8,8,8,8,8,8,8,8],
[1,1,1,1,1,1,1,1], [2,2,2,2,2,2,2,2],[3,3,3,3,3,3,3,3],[4,4,4,4,4,4,4,4]]
def main():
strassen(A,B)
def strassen(A, B):
A = numpy.asarray(A)
B = numpy.asarray(B)
lengthA = len(A)
lengthB = len(B)
if lengthA == 2:
print "will calculate"
else:
a, b = strassen(A[:lengthA//2, :lengthA//2], B[:lengthB//2, :lengthB//2])
lengthA = lengthA//2
lengthB = lengthB//2
print a
print b
return a, b
我正在尝试减少a
to[[5,5],[6,6]]
和b
to[[5,5],[6,6]]
但出现错误:
a, b = strassen(A[:lengthA//2, :lengthA//2], B[:lengthB//2, :lengthB//2])
TypeError: 'NoneType' object is not iterable.
a
并且b
是第一个 2x2 矩阵,将在 A 和 B 的第二次全矩阵除法之后形成。请有人向我解释一下。谢谢