输入基数后的第二个值后出现未知输出错误。
希望你们中的一些人可以识别我的错误：
错误：指令在 0x00400060 [0x00400060] 0x102a0000 beq $1, $10, 0 [hex-0x0040005c] 处引用未定义符号
进展：目前停留在第 2 步。
我想做的是，
1）用户输入一个十进制值
2）用户输入转换类型
3）根据之前选择的转换类型转到所需的子程序
4)显示输出
.data
prompt: .asciiz "Enter the decimal number to convert: "
base: .asciiz "Select type of base (2 for binary,16 for hexadecimal or 8 for octal): "
ans1: .asciiz "\nBinary Output is equivalent:"
ans2: .asciiz "\nOctal Output is equivalent:"
ans3: .asciiz "\nHexadecimal Output equivalent:0x"
result1: .space 8
.text
.globl main
main:
la $a0, prompt #Display message
li $v0, 4
syscall
li $v0, 5
syscall
beq $v0, $zero, Exit #Exit if 0 decimal is entered
move $t0, $v0 #Else copy value entered into temporaries
askbase:
li $v0, 4
la $a0, base #Display message
syscall
li $v0, 5
syscall
add $t1,$zero,$v0 #Add desired value/base entered into t1
beq $t2,16,hex #if base 16 is entered,goto hex subroutine
beq $t2,8,oct
beq $t2,2,bin
la $a0, ans3
li $v0, 4
syscall
li $t0, 8 # counter
la $t3, result1 # where answer will be stored
Hex:
beqz $t0, Exit # branch to exit if counter is equal to zero
rol $t2, $t2, 4 # rotate 4 bits to the left
and $t4, $t2, 0xf # mask with 1111
ble $t4, 9, Sum # if less than or equal to nine, branch to sum
addi $t4, $t4, 55 # if greater than nine, add 55
b End
Sum:
addi $t4, $t4, 48 # add 48 to result
End:
sb $t4, 0($t3) # store hex digit into result
addi $t3, $t3, 1 # increment address counter
addi $t0, $t0, -1 # decrement loop counter
j Loop
Exit: la $a0, result1
li $v0, 4
syscall
la $v0, 10
syscall