0

我想保存并加载充满历史条目对象的历史列表。我正在尝试通过独立存储来做到这一点，这样当用户打开和关闭应用程序时，他们的浏览历史记录都不会丢失。它被保存，一旦单击应用程序就可以加载它。我环顾四周并在stackoverflow上看到了这个问题，我试图遵循它但遇到了很多错误。隔离存储和保存多个对象。

这是代码

HistoryEntry 类

public string URL { get; set; }
public string timestamp { get; set; }
public string date { get; set; }

主页代码：

using System.Xml.Serialization;
using System.Collections.ObjectModel;
using System.IO;

List<HistoryEntry> urls = new List<HistoryEntry>();
public HistoryEntry selectedHistory;

public MainPage()
{
    InitializeComponent();
    Deserialize<>(urls, ???);
}

void Browser_Navigated(object sender, System.Windows.Navigation.NavigationEventArgs e)
{
     HistoryEntry urlObj = new HistoryEntry();
     urlObj.URL = url;
     urlObj.timestamp = DateTime.Now.ToString("HH:mm");
     urlObj.date = url.Remove(url.LastIndexOf('.'));
     urls.Add(urlObj);

     textBox1.Text = url;
     listBox.ItemsSource = null;
     listBox.ItemsSource = urls;

     Serialize(urlObj, urls);
}

private static void Serialize(string fileName, object source)
{
    var userStore = IsolatedStorageFile.GetUserStoreForApplication();
    using (var stream = new IsolatedStorageFileStream(fileName, FileMode.Create, userStore))
    {
        XmlSerializer serializer = new XmlSerializer(source.GetType());
        serializer.Serialize(stream, source);
    }
}

public static void Deserialize<T>(ObservableCollection<T> list, string filename)
{
    list = new ObservableCollection<T>();
    var userStore = IsolatedStorageFile.GetUserStoreForApplication();
    if (userStore.FileExists(filename))
    {
        using (var stream = new IsolatedStorageFileStream(filename, FileMode.Open, userStore))
        {
            XmlSerializer serializer = new XmlSerializer(list.GetType());
            var items = (ObservableCollection<T>)serializer.Deserialize(stream);
            foreach (T item in items)
            {
                list.Add(item);
            }
        }
    }
}

Serialize 有一些无效参数，与调用 De serialize 时相同。要发送到该方法的适当值是什么，这将成功保存和加载历史对象。

先感谢您 ：）

如果您需要更多详细信息，请发表评论，我很乐意进一步详细解释：）

4

1 回答 1

0

您是否尝试过这种MemoryStream适用于 Win 8 的方法：

至Serialize：

MemoryStream sessionData = new MemoryStream();
DataContractSerializer serializer = new 
DataContractSerializer(typeof(ObservableCollection<NewsByTag>));
serializer.WriteObject(sessionData, data);
StorageFile file = await ApplicationData.Current.LocalFolder
                     .CreateFileAsync(sFileName);
using (Stream fileStream = await file.OpenStreamForWriteAsync())
{
sessionData.Seek(0, SeekOrigin.Begin);
await sessionData.CopyToAsync(fileStream);
await fileStream.FlushAsync();
}

Deserialize回它：

StorageFile file = await ApplicationData.Current.LocalFolder.
                       GetFileAsync(sFileName);
using (IInputStream inStream = await file.OpenSequentialReadAsync())
{
DataContractSerializer serializer = 
new DataContractSerializer(typeof(ObservableCollection<NewsByTag>));
var data = (ObservableCollection<NewsByTag>)serializer
                 .ReadObject(inStream.AsStreamForRead());
}

希望能帮助到你！

于 2014-07-24T01:59:07.683 回答