sql - 如何将此 MySQL 语句转换为 named_scope 方法？

Question

“从用户中选择*，奖励其中（users.id = Awards.user_id）和awards.trophy_id不在（从awards.trophy_id = #{trophy.id}的奖励中选择awards.trophy_id）”

Answer 1

回答了自己的问题：

命名范围：not_awarded_trophy，lambda { |奖杯| { :include => :awards, :conditions => [ "awards.trophy_id 不在（从 Awards where Awards.trophy_id = ?) 中选择 Awards.trophy_id", trophy.id ] } }