我面临着可视化这个字符串的问题:
"=IF(A2=1;0;IF(D2=D3;IF(C2=1;TRUE;FALSE);4))";
如您所见,一般语法类似于 excel 公式,所以我有IF(TEST; TRUE; FALSE)
我的问题是我想用库 JUNG2 以二进制搜索树格式显示这个字符串。下面你可以看到一个树应该是什么样子的例子:
这里有一些代码可以显示当前的顶点。
public class SimpleGraphView {
Graph<Integer, String> g;
Graph<String, String> n;
/** Creates a new instance of SimpleGraphView */
String text = "=IF(A2=1;0;IF(D2=D3;IF(C2=1;TRUE;FALSE);4))";
public SimpleGraphView() {
n = new SparseMultigraph<String, String>();
String str = text;
String delim = ";";
StringTokenizer tok = new StringTokenizer(str, delim, true);
text = text.replace("(", " ");
String s = text.replace(")", " ");
String[] r = s.split(";");
for (int i = 0; i < r.length; i++) {
//Vertex
if(r.equals("=IF(")) {
n.addVertex(r[i].toString());
}
if(i % 2==0){
n.addVertex(r[i].toString());
} else {
n.addVertex(r[i].toString());
}
}
}
/**
* @param args the command line arguments
*/
public static void main(String[] args) {
SimpleGraphView sgv = new SimpleGraphView(); // Creates the graph...
// Layout<V, E>, VisualizationViewer<V,E>
Layout<Integer, String> layout = new CircleLayout(sgv.n);
layout.setSize(new Dimension(300,300));
VisualizationViewer<Integer,String> vv = new VisualizationViewer<Integer,String>(layout);
vv.setPreferredSize(new Dimension(350,350));
// Show vertex and edge labels
vv.getRenderContext().setVertexLabelTransformer(new ToStringLabeller());
vv.getRenderContext().setEdgeLabelTransformer(new ToStringLabeller());
// Create our "custom" mouse here. We start with a PluggableGraphMouse
// Then add the plugins you desire.
PluggableGraphMouse gm = new PluggableGraphMouse();
gm.add(new TranslatingGraphMousePlugin(MouseEvent.BUTTON1_MASK));
gm.add(new ScalingGraphMousePlugin(new CrossoverScalingControl(), 0, 1.1f, 0.9f));
vv.setGraphMouse(gm);
JFrame frame = new JFrame("Interactive Graph View 3");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.getContentPane().add(vv);
frame.pack();
frame.setVisible(true);
}
}
我可以从数组中的字符串中渲染所有顶点r
。我的问题是我不知道如何将所有这些顶点与正确的边缘连接起来。任何建议,如何将所有顶点与右边缘连接起来?
我真的很感谢你的回答!