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我有一个图表,它代表一个由两个较小进程组成的大进程。每个较小的过程都由一个子图表示。但是,当我将其中一个子流程(假设“一个”)的结尾连接到另一个(“两个”)的开头时,另一个流程(“两个”)的起始形状最终与“一”的结尾。如何让箭头从一个的末尾指向两个的开头,但将两个的起始形状保持在其簇内?

digraph BigProcess {
   graph [ label="Some big process" ]

   subgraph clusterSubProcess1 {
      graph [ label="Subprocess one", color="red" ]

      start1_1 -> start1_2;
      start1_2 -> start1_3a;
      start1_2 -> start1_3b;
      start1_3a -> start1_4;
      start1_3b -> start1_5;
      start1_4 -> start1_1;
      start1_5 -> start2_1;

   }

   subgraph clusterSubProcess2 {
      graph [ label="Subprocess two", color="blue" ]

      start2_1 -> start2_2;
      start2_2 -> start2_3a;
      start2_2 -> start2_3b;
      start2_3a -> start2_4;
      start2_3b -> start2_5;
      start2_4 -> start2_1;
      start2_5 -> end1;

   }
}

这导致以下结果,我真的希望 start2_1 成为蓝色有界框中的顶部节点。

这张图

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1 回答 1

8

发生这种情况是因为start1_5 -> start2_1;第一个子图中的线是在该子图中定义start2_1的。您需要start1_5在第一个子图中定义,但在您start2_1在第二个子图中定义之前将其保持未连接状态。

digraph BigProcess {
   graph [ label="Some big process" ]

   subgraph clusterSubProcess1 {
      graph [ label="Subprocess one", color="red" ]

      start1_1 -> start1_2;
      start1_2 -> start1_3a;
      start1_2 -> start1_3b;
      start1_3a -> start1_4;
      start1_3b -> start1_5;
      start1_4 -> start1_1;
      start1_5;

   }

   subgraph clusterSubProcess2 {
      graph [ label="Subprocess two", color="blue" ]

      start2_1 -> start2_2;
      start2_2 -> start2_3a;
      start2_2 -> start2_3b;
      start2_3a -> start2_4;
      start2_3b -> start2_5;
      start2_4 -> start2_1;
      start2_5 -> end1;

   }

   //Now connect the nodes in the two different subgraphs
   start1_5 -> start2_1;
}

所需子图中的节点

于 2014-04-18T23:24:25.430 回答