10

我正在创建一个能够一次上传多个图像的图像上传器。

galerijButton.setOnClickListener(new OnClickListener() {
    @Override
    public void onClick(View v) {
        Intent photoPickerIntent = new Intent(Intent.ACTION_PICK);
        photoPickerIntent.putExtra(Intent.EXTRA_ALLOW_MULTIPLE, true);

        photoPickerIntent.setType("image/*");
        startActivityForResult(photoPickerIntent, SELECT_PHOTO);   
    }
});

...

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent imageReturnedIntent) { 
    super.onActivityResult(requestCode, resultCode, imageReturnedIntent); 

    switch(requestCode) { 
    case SELECT_PHOTO:
        if(resultCode == RESULT_OK){  
            if(imageReturnedIntent.getData() != null){
                //If uploaded with Android Gallery (max 1 image)
                Uri selectedImage = imageReturnedIntent.getData();
                InputStream imageStream;
                try {
                    imageStream = getContentResolver().openInputStream(selectedImage);
                    Bitmap yourSelectedImage = BitmapFactory.decodeStream(imageStream);
                    photos.add(yourSelectedImage);
                } catch (FileNotFoundException e) {
                    e.printStackTrace();
                }
            } else {
                //If uploaded with the new Android Photos gallery
                ClipData clipData = imageReturnedIntent.getClipData();
                for(int i = 0; i < clipData.getItemCount(); i++){
                    clipData.getItemAt(i);
                    //What now?
                }
            }
        }
    break;
    ....

我想将所有选定的图像添加到我的照片数组中，这是一个ArrayList<Bitmap>. 我必须以某种方式将其转换ClipData.Item为Bitmap，但是如何？

4

3 回答 3

22

试试这个

ClipData.Item item = clip.getItemAt(i);
Uri uri = item.getUri();

现在您有了图像的URI。

我想你现在知道该怎么做了。干杯:)

于 2014-02-13T10:39:08.873 回答
0

您将图像编码为字符串，当您想使用它时将其解码回图像。

对于图像列表，创建一个字符串数组并将这些图像保存在其中。

public static String encodeTobase64(Bitmap image) {
    Bitmap immage = image;
    ByteArrayOutputStream baos = new ByteArrayOutputStream();
    immage.compress(Bitmap.CompressFormat.JPEG, 100, baos);
    byte[] b = baos.toByteArray();
    String imageEncoded = Base64.encodeToString(b, Base64.DEFAULT);
    Log.d("Image Log:", imageEncoded);
    return imageEncoded;
}

public static Bitmap decodeBase64(String input) {
    try {
        byte[] encodeByte = Base64.decode(input, Base64.DEFAULT);
        InputStream is = new ByteArrayInputStream(encodeByte);
        BitmapFactory.Options options = new BitmapFactory.Options();
        options.inPreferredConfig = Config.ALPHA_8;
        options.inSampleSize = 2;
        Bitmap bitmap = BitmapFactory.decodeStream(is, null, options);
        return bitmap;
    } catch (Exception e) {
        e.getMessage();
        return null;
    }
}
于 2014-02-13T10:32:08.830 回答
0

使用 Kotlin one liner 实现：

private fun ClipData.convertToList(): List<Uri> = 0.until(itemCount).map { getItemAt(it).uri }
于 2021-03-13T16:34:34.593 回答