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用pygame编写了一个小程序后，我遇到了一个问题。该程序采用拆分的 .GIF 动画并通过以下方式加载图像（gif 帧）：

pygame.image.load(filename)

这将返回一个 pygame 表面对象，然后将其附加到一个数组中。该程序将大约15 帧加载到一个数组中，总共使用6 个数组。

我遇到的问题是通过我的while 循环接受输入时。循环播放其空闲动画和运行动画很好，但是，在接受来自键盘的输入时（从 pygame 的事件列表中获取输入......）

for event in pygame.event.get():通过pygame.KEYDOWN

有非常明显的滞后，导致动画集切换反应迟钝。如果我要使用这种方法制作游戏，则必须对其进行修复。我确定我的代码效率低下，但不产生暂停就足够了。任何帮助都会很棒。

我猜？pygame.clock.tick()正在创建某种事件滞后，但我不确定如何解决这个问题，如果事件滞后甚至是这种情况。

这是我怀疑有问题的循环：

while running == 2:
pygame.display.flip()
#mouse = pygame.mouse.get_pos()
#events = pygame.event.get()
#(pygame.QUIT, pygame.KEYDOWN, pygame.KEYUP)
for event in pygame.event.get():
#event = pygame.event.wait()
    if event.type == pygame.QUIT:
        sys.exit(0)
    elif event.type == pygame.KEYDOWN:
        print event.key
        wait = 0
        if event.key == pygame.K_d:
            tmpcache = wr
            lastkey = "wr"
        elif event.key == pygame.K_a:
            tmpcache = wl
            lastkey = "wl"
    elif event.type == pygame.KEYUP:
        wait = 1
        if lastkey == "wr":
            tmpcache = sr
        elif lastkey == "wl":
            tmpcache = sl

if wait == 1:           
    for frame in tmpcache:
        screen.blit(test, (0,0))
        screen.blit(frame, (currentchar.posx, currentchar.posy))
        pygame.display.flip()
        clock.tick(charfps)

else:
    for frame in tmpcache:
        screen.blit(test, (0,0))
        screen.blit(frame, (currentchar.posx, currentchar.posy))
        pygame.display.flip()
        clock.tick(charfps)

此处未显示一些变量，但已使用：

charfps = 30
currentchar.posx, currentchar.posy两个元组都设置在(300, 240)

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1 回答 1

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您的问题是您在主循环中创建了子循环：

while running == 2:
    pygame.display.flip()
    for event in pygame.event.get():
        ...
    for frame in tmpcache:
        screen.blit(test, (0,0))
        screen.blit(frame, (currentchar.posx, currentchar.posy))
        pygame.display.flip()
        clock.tick(charfps)

因此，如果 中有 15 个元素，则每帧tmpcache调用clock.tick()15 次，并且当代码在此子循环内运行时，您不会继续进行事件。

只需调用pygame.display.flip()并且每帧clock.tick(charfps) 仅调用一次即可解决您的问题。

下面是一个简单的例子，以 60 FPS 运行时，每秒更改动画图像 3 次：

import pygame
from collections import deque

pygame.init()
screen = pygame.display.set_mode((300, 300))
clock = pygame.time.Clock()

# just some colored squares for our animation
def get_cache(colors):
    tmp=[]
    for c in colors:
        s = pygame.surface.Surface((50,50))
        s.fill(pygame.color.Color(c))
        tmp.append(s)
    return tmp

walk_left, walk_right = get_cache(('red', 'yellow', 'blue')), get_cache(('black', 'white', 'grey'))

rect = walk_left[0].get_rect(top=100, right=100)
cachedeque = deque(walk_left)
state = None
quit = False

# a simple variable to keep track of time
timer = 0

# a dict of {key: (animation, direction)}
moves = {pygame.K_LEFT:  (walk_left,  (-2, 0)),
         pygame.K_RIGHT: (walk_right, ( 2, 0))}

while not quit:
    quit = pygame.event.get(pygame.QUIT)
    pygame.event.poll()

    # state of the keys
    keys = pygame.key.get_pressed()

    # filter for the keys we're interessted in
    pressed = ((key, _) for (key, _) in moves.iteritems() if keys[key])
    key, (cache, dir) = next(pressed, (None, (None, None)))

    # if a key of the 'moves' dict is pressed:
    if key:
        # if we change the direction, we need another animation
        if state != key: 
            cachedeque = deque(cache)
            state = key
        # move the square                
        rect.move_ip(dir) 
    else:
        state = None

    screen.fill(pygame.color.Color('green'))

    # display first image in cachedeque    
    screen.blit(cachedeque[0], rect)

    # rotate cachedeque to the left, so the second image becomes the first
    # do this three times a second:
    if state and timer >= 1000./3:
        cachedeque.rotate(-1)
        timer = 0

    # call flip() and tick() only once per frame
    pygame.display.flip()

    # keep track of how long it took to draw this frame
    timer += clock.tick(60)

在此处输入图像描述

于 2014-01-30T13:14:27.237 回答