问题是：我想在对父行进行排序时将子行与父行一起移动。我正在使用这个 js 对我的表数据进行排序。我的 html 就像
<table>
<tr class="parent">
<th id="apple">Apple</th>
<th id="orange">Orange</th>
<th>Banana</th>
</tr>
<tr class="parent">
<td>Apple</td>
<td>Orange</td>
<td>Banana</td>
</tr>
<tr class="child">
<td>Apple 1</td>
<td>Orange 1</td>
<td>Banana 1</td>
</tr>
<tr class="child">
<td>Apple 2</td>
<td>Orange 2</td>
<td>Banana 2</td>
</tr>
<tr class="parent">
<td>Table</td>
<td>cHAIR</td>
<td>Mouse</td>
</tr>
<tr class="child">
<td>Table 1</td>
<td>cHAIR 1</td>
<td>Mouse 1</td>
</tr>
<tr class="child">
<td>Table 2</td>
<td>cHAIR 2</td>
<td>Mouse 2</td>
</tr>
</table>
js是这样的：
jQuery.fn.sortElements = (function(){
var sort = [].sort;
return function(comparator, getSortable) {
getSortable = getSortable || function(){return this;};
var placements = this.map(function(){
var sortElement = getSortable.call(this),
parentNode = sortElement.parentNode,
// Since the element itself will change position, we have
// to have some way of storing its original position in
// the DOM. The easiest way is to have a 'flag' node:
nextSibling = parentNode.insertBefore(
document.createTextNode(''),
sortElement.nextSibling
);
return function() {
if (parentNode === this) {
throw new Error(
"You can't sort elements if any one is a descendant of another."
);
}
// Insert before flag:
parentNode.insertBefore(this, nextSibling);
// Remove flag:
parentNode.removeChild(nextSibling);
};
});
return sort.call(this, comparator).each(function(i){
placements[i].call(getSortable.call(this));
});
};
})();
添加另一个JS：
$('#apple, #orange')
.each(function(){
var th = $(this),
thIndex = th.index(),
inverse = false;
th.click(function() {
// sorting classes don't work here b/c this function gets called repeatedly - moved to afterRequest: function
table.find('tr.parent td').filter(function(){
return $(this).index() === thIndex;
}).sortElements(function(a, b){
return $.text([a]) > $.text([b]) ?
inverse ? -1 : 1
: inverse ? 1 : -1;
}, function(){
// parentNode is the element we want to move
return this.parentNode;
// this.parentNode
});
inverse = !inverse;
});
});