linux - Bash script manipulation

Question

I work with Bash script and I want to get line from big text by special text

for example i have these lines

first fffffffffffffffffffffffffff
.................................
second ssssssssssssssssssssssssss
.................................
third ttttttttttttttttttttttttttt

and I want to get ssssssssssssssssssssssssss string .

Can anybody help me?

Answer 1

cat filename | grep "^second" | cut -d " " -f 2

或者，如果您是 ALF：

<filename grep "^second" | cut -d " " -f 2

或者

grep "^second" filename | cut -d " " -f 2

Answer 2

这是你想要的吗？

echo "$longstring" | awk '$1 == "second" { print $2 }'

Answer 3

由于您似乎没有关于要输出哪一行的任何标准，我建议如下：

echo "ssssssssssssssssssssssssss"

这对于您的输入内容非常强大，不依赖于“文件”，并且是一个快速的解决方案。