1

因此，我有一长串这样的单词，并且基于第一个空格，我想将单词拆分为word-meaning。基本上我正在使用Apache POI它，因为我必须读取 docx 文件，然后从中获取数据。

    abash  humiliate, embarrass
    abdicate  relinquish power or position
    aberrant  abnormal
    abet  aid, encourage (typically of crime)
    abeyance  postponement
    aboriginal  indigenous 
    abridge  shorten
    abstemious  moderate
...

那么什么正则表达式适合我的目的，以便我可以像这样显示它：

word :abash
meaning : humiliate, embarrass
...

我的代码是：

public class WordFileReader {

    /**
     * @param args
     */
    public static void main(String[] args) {
         try {
                FileInputStream fis = new FileInputStream("E:\\important.docx");
                org.apache.poi.xwpf.extractor.XWPFWordExtractor oleTextExtractor = new XWPFWordExtractor(new XWPFDocument(fis));
                System.out.print(oleTextExtractor.getText());            
            } catch (Exception e) {
                    e.printStackTrace();
            }

    }

}

--编辑--根据建议的答案，我正在使用这个

public static void main(String[] args) {
         try {
                FileInputStream fis = new FileInputStream("E:\\Words.docx");
                org.apache.poi.xwpf.extractor.XWPFWordExtractor oleTextExtractor = new XWPFWordExtractor(new XWPFDocument(fis));
                //System.out.print(oleTextExtractor.getText());

                Scanner sc = new Scanner(oleTextExtractor.getText());            
                while(sc.hasNextLine()) {
                 String line = sc.nextLine();
                 int i = line.indexOf(' ');
                 String word = line.substring(0, i);
                 String meaning = line.substring(i).trim();

                 System.out.println("word "+word);
                 System.out.println("meaning "+meaning);
                }

            } catch (Exception e) {
                    e.printStackTrace();
            }

    }

但我明白了

java.lang.StringIndexOutOfBoundsException: String index out of range: -1
    at java.lang.String.substring(Unknown Source)
    at WordFileReader.main(WordFileReader.java:25)
4

4 回答 4

3

我会使用 java.util.Scanner 从文本中提取行

Scanner sc = new Scanner(oleTextExtractor.getText());            
while(sc.hasNextLine()) {
    String line = sc.nextLine();
    ...

然后我会把这条线分成单词和含义

 int i = line.indexOf(' ', 2);  // start from pos 2 to avoid a article
 String word = txt.substring(0, i);
 String meaning = txt.substring(i).trim();

或者

 String[] parts = line.split("(?<!^a)\\s+", 2);
 String word = parts[0];
 String meaning = parts[1];
于 2013-06-10T08:44:26.043 回答
1

使用java.lang.String.split(String regex, int limit)：

String[] parts = line.split("\\s", 1)
String word = parts[0];
String meaning = parts[1];
于 2013-06-10T08:37:28.877 回答
0

您可以按如下方式使用子字符串：

int index = line.indexOf(" ");

"word : "+ line.substring(0, index)+"\n 含义： "+line.substring(index+1)

于 2013-06-10T08:41:04.210 回答
0

下面的代码对我来说很好。我使用 BufferedReader 从文件中读取文本。

BufferedReader br=null;
    try {
        br = new BufferedReader(new FileReader("C:\\test.txt"));
    } catch (FileNotFoundException ex) {
        Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex);
    }
try {
    StringBuilder sb = new StringBuilder();
    String line="";
    String [] parts=null;
    String everything="",word="",meaning="";
        try {
            line = br.readLine();
        } catch (IOException ex) {
            Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex);
        }

    while (line != null) {
        sb.append(line);

        parts= line.split(" ",2);
        word=parts[0];
        meaning=parts[1];

    System.out.println("word:"+word.toString());
    System.out.println("meaning:"+meaning.toString());

        sb.append("\n");
            try {
                line = br.readLine();
            } catch (IOException ex) {
                Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex);
            }
    }

} finally {
        try {
            br.close();

        } catch (IOException ex) {
            Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex);
        }
}
于 2013-06-10T09:19:06.837 回答