3

我有一个这样NSMutableArray的NSDictionary东西：

myArray (
    {
    chatins = 20;
    placeImageString = 244211112265925;
},
    {
    chatins = 5;
    placeImageString = 154909144575109;
},
    {
    chatins = 30;
    placeImageString = 193867280641162;
},
    {
    chatins = 13;
    placeImageString = 224627130902;
},

)

另一个NSMutableArray是NSDictionary这样的：

myArray2 
(
    {
    category = "Local business";
    distance = "0.1";
    name = "Mts India";
    placeImageString = 244211112265925;
},
    {
    category = "Local business";
    distance = "0.17";
    name = "Aegis Ltd";
    placeImageString = 154909144575109;
},
    {
    category = "Automobiles and parts";
    distance = "0.19";
    name = Autopsyche;
    placeImageString = 78480207511;
},
    {
    category = Company;
    distance = "0.19";
    name = "The Oberoi, Gurgaon";
    placeImageString = 121676041233945;
},

)

我想合并myArray并myArray2得到s 的结果NSMutableArray，NSDictionary如下所示，其中 myplaceImageString是匹配两个字典数组中数据的键，如果在其中找不到键，myArray2则键的值chatins应为 0。

myArray3 
(
{
category = "Local business";
distance = "0.1";
name = "Mts India";
placeImageString = 244211112265925;
 chatins = 20;

},
{
category = "Local business";
distance = "0.17";
name = "Aegis Ltd";
placeImageString = 154909144575109;
chatins = 5;

},
{
category = "Automobiles and parts";
distance = "0.19";
name = Autopsyche;
placeImageString = 78480207511;
chatins = 0;


},
    {
    category = Company;
    distance = "0.19";
    name = "The Oberoi, Gurgaon";
    placeImageString = 121676041233945;
    chatins = 0;

    },
)
4

2 回答 2

2

在这里，我为您提供了一个示例代码：

  NSMutableArray *array1 = [[NSMutableArray alloc] init];
  NSMutableArray *array2 = [[NSMutableArray alloc] init];


  NSMutableDictionary * dict = [[NSMutableDictionary alloc]
                                initWithObjects:[NSArray arrayWithObjects:@"1",@"ABC", nil]
                                forKeys:[NSArray arrayWithObjects:@"ID",@"NAME", nil]];
  [array1 addObject:dict];

  dict = nil;

  /*
   Same way added 2 more dictionaries to the same array - array1
   */

  NSLog(@"array1: %@", array1);


  dict = nil;

  dict = [[NSMutableDictionary alloc]
          initWithObjects:[NSArray arrayWithObjects:@"1",@"DEF", nil]
          forKeys:[NSArray arrayWithObjects:@"ID",@"ADDRESS", nil]];

  [array2 addObject:dict];

  dict = nil;

  /*
   Same way added 2 more dictionaries to the same array - array2
   */


  NSLog(@"array2: %@", array2);


  for (int index = 0; index < [array1 count]; index ++) {

    NSMutableDictionary *dict1 = [array1 objectAtIndex:index];

    for (NSMutableDictionary *dict2 in array2) {

      if ([[dict1 objectForKey:@"ID"] isEqualToString:
           [dict2 objectForKey:@"ID"]]) {

        [dict1 setObject:[dict2 objectForKey:@"ADDRESS"] forKey:@"ADDRESS"];
      }
    }
  }

现在最后，如果您检查array1 ，所有这些字典中都会添加一个键（ADDRESS ）。

希望这有帮助。

-Mrunal

于 2013-01-23T15:37:05.810 回答
0 
1. Create a new empty NSMutableArray newArray
2. Loop through all NSDictionaries of myArray2

    a. Copy the current NSDictionary to a new NSMutableDictionary newDict
    b. Loop through myArray1
        b1. if myArray1.dict.placeImageString == newDict.placeImageString
            - Add myArray1.dict.chatins to newDict
            - break out of loop
    c. add newDict to newArray
于 2013-01-23T15:32:35.690 回答