1

当我尝试远程登录到服务器时，代码永远不会到达print 'never reach1'or行。print 'never reach2'

import sys, signal
from gevent.server import StreamServer
from gevent.pool import Pool
from gevent import monkey
import gevent
from gevent import Timeout
import random

class SocketPool(object):

    def __init__(self):
        self.pool = Pool(1000)

    def listen(self, socket):
        while True:
            line = socket.recv(1024)
            print line

    def add_handler(self, socket, address):
        if self.pool.full():
            raise Exception("At maximum pool size")
        else:
            self.pool.spawn(self.listen, socket)
            gevent.spawn(self.wait).join()

    def wait(self):
        try:
            timeout = Timeout(1)
            timeout.start()
        except Timeout:
            print 'never reach1'
        except:
            print 'never reach2'

    def shutdown(self): self.pool.kill()

def signal_handler(signal, frame): sys.exit(0)

signal.signal(signal.SIGINT, signal_handler)
monkey.patch_all()
sockPool = SocketPool()
server = StreamServer(('127.0.0.1', 5000), sockPool.add_handler)
server.serve_forever()
4

1 回答 1

2

正如您从文档中看到的：

timeout = Timeout(seconds, exception)
timeout.start()
try:
    ...  # exception will be raised here, after *seconds* passed since start() call
finally:
    timeout.cancel()

因此，您的try块已完全执行，因此无法捕获异常。您应该放置一个while循环或计算之类的东西，至少需要 1 秒才能看到异常。

如果你想创建一个简单“休眠”而不使用 CPU 的方法，我建议使用 simpletime.sleep而不是使用Timeout.

于 2013-01-17T06:39:35.097 回答