201

我们如何使用 Eloquent ORM 在 Laravel 中执行批量数据库插入？

我正在处理一个 XML 文档，循环遍历它的元素。我想在 Laravel 中完成这样的事情：

$sXML = download_page('http://remotepage.php&function=getItems&count=100&page=1');
$oXML = new SimpleXMLElement($sXML);
$query = "INSERT INTO tbl_item (first_name, last_name, date_added) VALUES";
foreach($oXML->results->item->item as $oEntry){
    $query .=  "('" . $oEntry->firstname . "', '" . $oEntry->lastname . "', '" . date("Y-m-d H:i:s") . "'),";
}
mysql_query($query);

但我收到以下错误。

SQLSTATE[HY093]：无效参数号：混合命名参数和位置参数。

4

11 回答 11

375

你可以只使用Eloquent::insert().

例如：

$data = [
    ['name'=>'Coder 1', 'rep'=>'4096'],
    ['name'=>'Coder 2', 'rep'=>'2048'],
    //...
];

Coder::insert($data);
于 2012-11-27T23:54:16.433 回答
91

我们可以更新 GTF 答案以轻松更新时间戳

$data = array(
    array(
        'name'=>'Coder 1', 'rep'=>'4096',
        'created_at'=>date('Y-m-d H:i:s'),
        'modified_at'=> date('Y-m-d H:i:s')
       ),
    array(
         'name'=>'Coder 2', 'rep'=>'2048',
         'created_at'=>date('Y-m-d H:i:s'),
         'modified_at'=> date('Y-m-d H:i:s')
       ),
    //...
);

Coder::insert($data);

更新：为了简化日期，我们可以按照@Pedro Moreira 的建议使用碳

$now = Carbon::now('utc')->toDateTimeString();
$data = array(
    array(
        'name'=>'Coder 1', 'rep'=>'4096',
        'created_at'=> $now,
        'modified_at'=> $now
       ),
    array(
         'name'=>'Coder 2', 'rep'=>'2048',
         'created_at'=> $now,
         'modified_at'=> $now
       ),
    //...
);

Coder::insert($data);

UPDATE2：对于 laravel 5 ，使用updated_at代替modified_at

$now = Carbon::now('utc')->toDateTimeString();
$data = array(
    array(
        'name'=>'Coder 1', 'rep'=>'4096',
        'created_at'=> $now,
        'updated_at'=> $now
       ),
    array(
         'name'=>'Coder 2', 'rep'=>'2048',
         'created_at'=> $now,
         'updated_at'=> $now
       ),
    //...
);

Coder::insert($data);
于 2014-10-26T05:01:21.577 回答
36

这就是你如何以更雄辩的方式做到这一点，

    $allinterests = [];
    foreach($interests as $item){ // $interests array contains input data
        $interestcat = new User_Category();
        $interestcat->memberid = $item->memberid;
        $interestcat->catid = $item->catid;
        $allinterests[] = $interestcat->attributesToArray();
    }
    User_Category::insert($allinterests);
于 2017-06-04T12:12:59.637 回答
30

对于正在阅读本文的人，请查看createMany()方法。

/**
 * Create a Collection of new instances of the related model.
 *
 * @param  array  $records
 * @return \Illuminate\Database\Eloquent\Collection
 */
public function createMany(array $records)
{
    $instances = $this->related->newCollection();

    foreach ($records as $record) {
        $instances->push($this->create($record));
    }

    return $instances;
}
于 2017-01-25T19:18:26.960 回答
7

我搜索了很多次，最后使用自定义timestamps如下：

$now = Carbon::now()->toDateTimeString();
Model::insert([
    ['name'=>'Foo', 'created_at'=>$now, 'updated_at'=>$now],
    ['name'=>'Bar', 'created_at'=>$now, 'updated_at'=>$now],
    ['name'=>'Baz', 'created_at'=>$now, 'updated_at'=>$now],
    ..................................
]);
于 2017-12-23T19:28:18.140 回答
4

Eloquent::insert是正确的解决方案，但它不会更新时间戳，因此您可以执行以下操作

 $json_array=array_map(function ($a) { 
                        return array_merge($a,['created_at'=> 
                                            Carbon::now(),'updated_at'=> Carbon::now()]
                                           ); 
                                     }, $json_array); 
 Model::insert($json_array);

这个想法是在插入之前在整个数组上添加 created_at 和 updated_at

于 2019-02-16T03:16:14.860 回答
0 
$start_date = date('Y-m-d h:m:s');        
        $end_date = date('Y-m-d h:m:s', strtotime($start_date . "+".$userSubscription['duration']." months") );
        $user_subscription_array = array(
          array(
            'user_id' => $request->input('user_id'),
            'user_subscription_plan_id' => $request->input('subscription_plan_id'),
            'name' => $userSubscription['name'],
            'description' => $userSubscription['description'],
            'duration' => $userSubscription['duration'],
            'start_datetime' => $start_date,
            'end_datetime' => $end_date,
            'amount' => $userSubscription['amount'],
            'invoice_id' => '',
            'transection_datetime' => '',
            'created_by' => '1',
            'status_id' => '1', ),
array(
            'user_id' => $request->input('user_id'),
            'user_subscription_plan_id' => $request->input('subscription_plan_id'),
            'name' => $userSubscription['name'],
            'description' => $userSubscription['description'],
            'duration' => $userSubscription['duration'],
            'start_datetime' => $start_date,
            'end_datetime' => $end_date,
            'amount' => $userSubscription['amount'],
            'invoice_id' => '',
            'transection_datetime' => '',
            'created_by' => '1',
            'status_id' => '1', )
        );
        dd(UserSubscription::insert($user_subscription_array));

UserSubscription是我的型号名称。如果插入成功，则返回“true”，否则返回“false”。

于 2016-08-27T09:32:42.377 回答
0

也许解决这个问题的更 Laravel 方法是使用一个集合并将其循环插入模型中，利用时间戳。

<?php

use App\Continent;
use Illuminate\Database\Seeder;

class InitialSeeder extends Seeder
{
    /**
     * Run the database seeds.
     *
     * @return void
     */
    public function run()
    {
        collect([
            ['name' => 'América'],
            ['name' => 'África'],
            ['name' => 'Europa'],
            ['name' => 'Asia'],
            ['name' => 'Oceanía'],
        ])->each(function ($item, $key) {
            Continent::forceCreate($item);
        });
    }
}

编辑：

对不起，我的误解。对于批量插入，这可能会有所帮助，也许您可​​以制作好的播种机并对其进行一些优化。

<?php

use App\Continent;
use Carbon\Carbon;
use Illuminate\Database\Seeder;

class InitialSeeder extends Seeder
{
    /**
     * Run the database seeds.
     *
     * @return void
     */
    public function run()
    {
        $timestamp = Carbon::now();
        $password = bcrypt('secret');

        $continents = [
            [
                'name' => 'América'
                'password' => $password,
                'created_at' => $timestamp,
                'updated_at' => $timestamp,
            ],
            [
                'name' => 'África'
                'password' => $password,
                'created_at' => $timestamp,
                'updated_at' => $timestamp,
            ],
            [
                'name' => 'Europa'
                'password' => $password,
                'created_at' => $timestamp,
                'updated_at' => $timestamp,
            ],
            [
                'name' => 'Asia'
                'password' => $password,
                'created_at' => $timestamp,
                'updated_at' => $timestamp,
            ],
            [
                'name' => 'Oceanía'
                'password' => $password,
                'created_at' => $timestamp,
                'updated_at' => $timestamp,
            ],
        ];

        Continent::insert($continents);
    }
}
于 2017-09-21T23:28:23.533 回答
0

从 Laravel 5.7 开始，Illuminate\Database\Query\Builder您可以使用 insertUsing 方法。

$query = [];
foreach($oXML->results->item->item as $oEntry){
    $date = date("Y-m-d H:i:s")
    $query[] = "('{$oEntry->firstname}', '{$oEntry->lastname}', '{$date}')";
}

Builder::insertUsing(['first_name', 'last_name', 'date_added'], implode(', ', $query));
于 2020-03-05T00:02:12.323 回答
-4

对于类别关系插入，我遇到了同样的问题并且不知道，除了在我雄辩的模型中，我使用 Self() 在 foreach 中有一个相同类的实例来记录多个保存和抓取 id。

foreach($arCategories as $v)
{                
    if($v>0){
        $obj = new Self(); // this is to have new instance of own
        $obj->page_id = $page_id;
        $obj->category_id = $v;
        $obj->save();
    }
}

没有 "$obj = new Self()" 它只保存一条记录（当 $obj 是 $this 时）

于 2019-06-16T09:00:48.227 回答
-6

问题已解决... 更改表以进行迁移

$table->timestamp('created_at')->nullable()->useCurrent();

解决方案：

Schema::create('spider_news', function (Blueprint $table) {
    $table->bigIncrements('id');
    $table->string('source')->nullable();
    $table->string('title')->nullable();
    $table->string('description')->nullable();
    $table->string('daterss')->nullable();

    $table->timestamp('created_at')->useCurrent();
    $table->timestamp('updated_at')->useCurrent();
});
于 2019-06-14T17:43:52.937 回答