7

我有桌子

ID     State        District        StationCode        Status
---------------------------------------------------------------
 1    Gujarat       Banaskantha      12345               0 
 2    Gujarat       Banaskantha      12345               0
 3    M.P.          Bhopal           22315               1
 4    Gujarat       Banaskantha      12349               0
 5    Gujarat       Banaskantha      12345               1

我需要像这样的结果 

State      District       Active       InActive
-----------------------------------------------
Gujarat     Banaskantha      2            1
M.P.        Bhopal           0            1

在这里，Active 和字段是基于或Inactive的字段的总和Status01

这意味着这里State对于古吉拉特邦，曾经three发生0过，但是two对于StationCode - 12345. 这意味着它将被视为One.

我有如下查询

select distinct 
    state,
    District,
    SUM(
        Case 
        when Status=0 then 1 
        else 0 end
        ) AS Active,
    SUM(
        Case 
            when Status=1 then 1 
            else 0 
        end
        ) AS InActive 
from 
    Station_Master 
group by state, District

但我无法将重复StationCode行计为单行。

我怎样才能做到这一点 ？

4

5 回答 5

4

您可以唯一地过滤子查询中的行。尝试，

SELECT  DISTINCT state, district,
        SUM(CASE WHEN status = 0 THEN 1 ELSE 0 END) Active,
        SUM(CASE WHEN status = 1 THEN 1 ELSE 0 END) InActive
FROM (
        SELECT DISTINCT state,  district, StationCode, status 
        FROM  Station_Master
    ) a
GROUP BY state, district

SQLFiddle 演示

于 2012-09-13T05:02:43.267 回答
2

在从中获取数据之前，您应该在子查询中使用子查询DISTINCT或子句：GROUP BY

使用DISTINCT子句：

SELECT  DISTINCT state, district,
        SUM(CASE WHEN status = 0 THEN 1 ELSE 0 END) Active,
        SUM(CASE WHEN status = 1 THEN 1 ELSE 0 END) InActive
FROM (
        SELECT DISTINCT state,  district, StationCode, status 
        FROM  Station_Master
     ) A
GROUP BY state, district;

使用GROUP BY子句：

SELECT 
    state,
    District,
    SUM(Case when Status=0 then 1 else 0 end) AS Active,
    SUM(Case when Status=1 then 1 else 0 end) AS InActive 
FROM
(
    SELECT state,District,StationCode,Status
    FROM Station_Master 
    GROUP BY state, District, Stationcode,Status
) A
GROUP BY state, District;

看到这个 SQLFiddle

我还在表中添加了几条记录来检查这个 SQLFiddle 中的查询。并且工作正常。

于 2012-09-13T05:50:10.767 回答
1

我认为这可能会解决您的问题。我不是 100% 确定语法，但如果你可以尝试一下，如果它不起作用，请告诉我，我可以尝试为你调整它。这个想法是使用 Group By 创建一个派生表，以首先消除您不想要的重复项，然后外部查询与您的原始查询相同 - 只是在派生表上。

SELECT Distinct 
  X.State, 
  X.District, 
  SUM(Case when X.Status=0 then 1 else 0 end) AS Active,
  SUM(Case when X.Status=1 then 1 else 0 end) AS InActive
FROM 
  (Select State, District, StationCode, Status
   From Station_Master 
   Group By State,District, StationCode, Status) as X
GROUP BY X.State, X.District
于 2012-09-13T05:11:33.797 回答
1

请使用以下 SQL：

declare @temptable table 
(
Id int,
state nvarchar(250),
District nvarchar(250),
StationCode nvarchar(250),
Status bit
)
Insert into @temptable values  (1,'Gujarat','Banaskantha','12345',0 )
Insert into @temptable values  (2,'Gujarat','Banaskantha','12345',0 )
Insert into @temptable values  (3,'M.P.','Bhopal','22315',1 )
Insert into @temptable values  (4,'Gujarat','Banaskantha','12349',0 )
Insert into @temptable values  (5,'Gujarat','Banaskantha','12345',1 )

select  tbl.state,tbl.District,SUM(cast(tbl.Status as int)) as Active ,(Count(*) -   
    SUM(cast(tbl.Status as int))) as InActive  
from (select distinct state,District,StationCode,Status from @temptable)as tbl 
group by tbl.state,tbl.District
于 2012-09-13T06:08:11.877 回答
0

首先检索 (State, District, Status) 的不同元组，然后在其上运行聚合查询，如下所示：

SELECT 
    a.state,
    a.District,
    SUM(
        Case 
        when a.Status=0 then 1 
        else 0 end
        ) AS Active,
    SUM(
        Case 
            when a.Status=1 then 1 
            else 0 
        end
        ) AS InActive 
from 
    (
        SELECT DISTINCT 
            state, 
            district, 
            status 
        FROM 
            Station_Master 
    ) as a
group by a.state, a.District
于 2012-09-13T05:04:35.597 回答