76

我有一个example.com/contact-us.php看起来像这样的表格（简化）：

<form method="post" action="process.php" enctype="multipart/form-data">
  <input type="file" name="uploaded_file" id="uploaded_file" />
  <input type="hidden" name="MAX_FILE_SIZE" value="10000000" />
</form>

在我的process.php文件中，我使用以下代码PHPMailer()发送电子邮件：

require("phpmailer.php");

$mail = new PHPMailer();

$mail->From     = me@example.com;
$mail->FromName = My name;
$mail->AddAddress(me@example.com,"John Doe");

$mail->WordWrap = 50;
$mail->IsHTML(true);

$mail->Subject  =  "Contact Form Submitted";
$mail->Body     =  "This is the body of the message.";

电子邮件正确发送正文，但没有uploaded_file.

我的问题

我需要将uploaded_file表单中的文件附加到电子邮件中并发送。process.php在脚本通过电子邮件发送文件后，我不关心保存文件。

我知道我需要在AddAttachment();某处添加（我假设在该Body行下方）以发送附件。但...

  1. 我在文件顶部放什么process.php来拉入文件uploaded_file？喜欢$_FILES['uploaded_file']从contact-us.php 页面中提取文件的东西吗？
  2. 文件附在里面AddAttachment();并与电子邮件一起发送，这段代码需要放在哪里？

请帮助并提供代码！谢谢！

4

8 回答 8

114

尝试：

if (isset($_FILES['uploaded_file']) &&
    $_FILES['uploaded_file']['error'] == UPLOAD_ERR_OK) {
    $mail->AddAttachment($_FILES['uploaded_file']['tmp_name'],
                         $_FILES['uploaded_file']['name']);
}

基本示例也可以在这里找到。

的函数定义为AddAttachment：

public function AddAttachment($path,
                              $name = '',
                              $encoding = 'base64',
                              $type = 'application/octet-stream')
于 2012-08-01T17:12:21.987 回答
7

无法从客户端 PC 附加文件（上传）

在 HTML 表单中，我没有添加以下行，所以没有附件：

enctype="多部分/表单数据"

在表格中添加上述行（如下）后，附件就完美了。

<form id="form1" name="form1" method="post" action="form_phpm_mailer.php"  enctype="multipart/form-data">
于 2012-12-15T19:07:49.650 回答
1

此代码帮助我发送附件....

$mail->AddAttachment($_FILES['file']['tmp_name'], $_FILES['file']['name']);

用上面的代码替换您的 AddAttachment(...) 代码

于 2016-06-02T10:50:11.503 回答
1

使用此代码在 phpmailer 中使用 html 表单发送带有上传文件选项的附件

 <form method="post" action="" enctype="multipart/form-data">


                    <input type="text" name="name" placeholder="Your Name *">
                    <input type="email" name="email" placeholder="Email *">
                    <textarea name="msg" placeholder="Your Message"></textarea>


                    <input type="hidden" name="MAX_FILE_SIZE" value="30000" />
                    <input type="file" name="userfile"  />


                <input name="contact" type="submit" value="Submit Enquiry" />
   </form>


    <?php




        if(isset($_POST["contact"]))
        {

            /////File Upload

            // In PHP versions earlier than 4.1.0, $HTTP_POST_FILES should be used instead
            // of $_FILES.

            $uploaddir = 'uploads/';
            $uploadfile = $uploaddir . basename($_FILES['userfile']['name']);

            echo '<pre>';
            if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) {
                echo "File is valid, and was successfully uploaded.\n";
            } else {
                echo "Possible invalid file upload !\n";
            }

            echo 'Here is some more debugging info:';
            print_r($_FILES);

            print "</pre>";


            ////// Email


            require_once("class.phpmailer.php");
            require_once("class.smtp.php");



            $mail_body = array($_POST['name'], $_POST['email'] , $_POST['msg']);
            $new_body = "Name: " . $mail_body[0] . ", Email " . $mail_body[1] . " Description: " . $mail_body[2];



            $d=strtotime("today"); 

            $subj = 'New enquiry '. date("Y-m-d h:i:sa", $d);

            $mail = new PHPMailer(); // create a new object


            //$mail->IsSMTP(); // enable SMTP
            $mail->SMTPDebug = 1; // debugging: 1 = errors and messages, 2 = messages only ,false = Disable 
            $mail->Host = "mail.yourhost.com";
            $mail->Port = '465';
            $mail->SMTPAuth = true; // enable 
            $mail->SMTPSecure = true;
            $mail->IsHTML(true);
            $mail->Username = "admin@domain.net"; //from@domainname.com
            $mail->Password = "password";
            $mail->SetFrom("admin@domain.net", "Your Website Name");
            $mail->Subject = $subj;
            $mail->Body    = $new_body;

            $mail->AddAttachment($uploadfile);

            $mail->AltBody = 'Upload';
            $mail->AddAddress("recipient@domain.com");
             if(!$mail->Send())
                {
                echo "Mailer Error: " . $mail->ErrorInfo;
                }
                else
                {

                echo '<p>       Success              </p> ';

                }

        }



?>

使用此链接作为参考。

于 2017-12-26T11:33:38.870 回答
1

这将完美地工作

    <form method='post' enctype="multipart/form-data">
    <input type='file' name='uploaded_file' id='uploaded_file' multiple='multiple' />
    <input type='submit' name='upload'/> 
    </form>

    <?php
           if(isset($_POST['upload']))
        {
             if (isset($_FILES['uploaded_file']) && $_FILES['uploaded_file']['error'] == UPLOAD_ERR_OK)
                {
                     if (array_key_exists('uploaded_file', $_FILES))
                        { 
                            $mail->Subject = "My Subject";
                            $mail->Body = 'This is the body';
                            $uploadfile = tempnam(sys_get_temp_dir(), sha1($_FILES['uploaded_file']['name']));
                        if (move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $uploadfile))
                             $mail->addAttachment($uploadfile,$_FILES['uploaded_file']['name']); 
                            $mail->send();
                            echo 'Message has been sent';
                        }       
                else
                    echo "The file is not uploaded. please try again.";
                }
                else
                    echo "The file is not uploaded. please try again";
        }
    ?>
于 2019-03-08T22:49:40.977 回答
0

您将使用$_FILES['uploaded_file']['tmp_name']，这是 PHP 存储上传文件的路径（它是一个临时文件，在脚本结束时由 PHP 自动删除，除非您已将其移动/复制到其他地方）。

假设您的客户端表单和服务器端上传设置是正确的，那么您无需做任何事情来“拉入”上传。它会神奇地在那个 tmp_name 路径中可用。

请注意，您必须验证上传是否实际成功，例如

if ($_FILES['uploaded_file']['error'] === UPLOAD_ERR_OK) {
    ... attach file to email ...
}

否则，您可能会尝试使用损坏/部分/不存在的文件制作附件。

于 2012-08-01T17:13:45.813 回答
0

嘿伙计们，下面的代码对我来说非常好。只需将 setFrom 和 addAddress 替换为您的偏好即可。

<?php
/**
 * PHPMailer simple file upload and send example.
 */
//Import the PHPMailer class into the global namespace
use PHPMailer\PHPMailer\PHPMailer;
use PHPMailer\PHPMailer\Exception;
$msg = '';
if (array_key_exists('userfile', $_FILES)) {
    // First handle the upload
    // Don't trust provided filename - same goes for MIME types
    // See http://php.net/manual/en/features.file-upload.php#114004 for more thorough upload validation
    $uploadfile = tempnam(sys_get_temp_dir(), hash('sha256', $_FILES['userfile']['name']));
    if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) 
    {
        // Upload handled successfully
        // Now create a message

        require 'vendor/autoload.php';
        $mail = new PHPMailer;
        $mail->setFrom('info@example.com', 'CV from Web site');
        $mail->addAddress('blabla@gmail.com', 'CV');
        $mail->Subject = 'PHPMailer file sender';
        $mail->Body = 'My message body';

        $filename = $_FILES["userfile"]["name"]; // add this line of code to auto pick the file name
        //$mail->addAttachment($uploadfile, 'My uploaded file'); use the one below instead

        $mail->addAttachment($uploadfile, $filename);
        if (!$mail->send()) 
        {
            $msg .= "Mailer Error: " . $mail->ErrorInfo;
        } 
        else 
        {
            $msg .= "Message sent!";
        }
    } 
        else 
        {
            $msg .= 'Failed to move file to ' . $uploadfile;
        }
}
?>
<!DOCTYPE html>
<html>
<head>
    <meta http-equiv="Content-Type" content="text/html; charset=utf-8">
    <title>PHPMailer Upload</title>
</head>
<body>
<?php if (empty($msg)) { ?>
    <form method="post" enctype="multipart/form-data">
        <input type="hidden" name="MAX_FILE_SIZE" value="4194304" />
        <input name="userfile" type="file">
        <input type="submit" value="Send File">
    </form>

<?php } else {
    echo $msg;
} ?>
</body>
</html>
于 2018-02-16T11:04:10.540 回答
0

在我自己的情况下，我serialize()在表单上使用，因此文件没有被发送到 php。如果您使用的是 jquery，请使用FormData(). 例如

<form id='form'>
<input type='file' name='file' />
<input type='submit' />
</form>

使用jQuery，

$('#form').submit(function (e) {
e.preventDefault();
var formData = new FormData(this); // grab all form contents including files
//you can then use formData and pass to ajax

});
于 2018-05-10T07:07:23.743 回答