sql - DB2 SQL 求和和分组

Question

我在查询和分组时遇到问题。

我需要以下输出：

officr, cbal, sname  
ABC, 500.00, TOM JONES  
ABC, 200.00, SUE JONES  
ABC TOTAL 700.00  

RAR, 100.10, JOE SMITH  
RAR, 200.05,  MILES SMITH  
RAR TOTAL 300.15  

下面的 SQL 产生错误：

[DB2 for i5/OS]SQL0122 - SELECT 列表中的列 SNAME 或表达式无效。

SELECT
    lnmast.officr,  SUM(LNMAST.CBAL), lnmast.sname
FROM
    LNMAST
WHERE LNMAST.RATCOD IN (6,7,8) AND STATUS NOT IN ('2','8')
group by lnmast.officr

Answer 1

GROUP BY GROUPING SETS是一个用于分组/立方体数据的强大工具。它允许您将非聚合数据与聚合数据组合在一个查询结果中。

SELECT lnmast.officr,  SUM(LNMAST.CBAL), lnmast.sname
FROM LNMAST
WHERE LNMAST.RATCOD IN (6,7,8) 
  AND STATUS NOT IN ('2','8')
GROUP BY GROUPING SETS ((lnmast.officr, lnmast.sname),(lnmast.officr))

来自 IBM DOCS 的示例：www.ibm.com/support/knowledgecenter/en/... ：

  SELECT WEEK(SALES_DATE) AS WEEK,
         DAYOFWEEK(SALES_DATE) AS DAY_WEEK,
         SALES_PERSON, SUM(SALES) AS UNITS_SOLD       
  FROM SALES 
  WHERE WEEK(SALES_DATE) = 13
  GROUP BY GROUPING SETS ( (WEEK(SALES_DATE), SALES_PERSON),
                           (DAYOFWEEK(SALES_DATE), SALES_PERSON))
  ORDER BY WEEK, DAY_WEEK, SALES_PERSON

这导致：

  WEEK        DAY_WEEK    SALES_PERSON    UNITS_SOLD 
  ----------- ----------- --------------- -----------
           13           - GOUNOT                   32
           13           - LEE                      33
           13           - LUCCHESSI                 8
            -           6 GOUNOT                   11
            -           6 LEE                      12
            -           6 LUCCHESSI                 4
            -           7 GOUNOT                   21
            -           7 LEE                      21
            -           7 LUCCHESSI                 4