我是 python 的初学者,并试图为学校程序及其 GUI 制作一个简单的登录系统。
我做得很好,因为我是 python 的初学者(和一般的编码),我正在努力学习使用 tkinter。
我已经弄清楚了一切,除非我试图让程序在用户“ access = True
”时更改标签文本。
这是代码片段:
from tkinter import *
from time import sleep
usernamelist = ["bob123","tim321","me","duda"]
passwordlist = ["banana","apple","password123","duda2000"]
def checklogin():
global access
global mode
username = entuser.get()
password = entpass.get()
userfound = False
if username == "admin":
if password == "allowmein":
access = True
mode = "admin"
else:
lberror.config(text="Incorrect password, try again")
entpass.delete(0, END)
else:
for i in range(len(usernamelist)):
if username == usernamelist[i]:
userfound = True
if password == passwordlist[i]:
access = True
else:
lberror.config(text="Incorrect password, try again")
entpass.delete(0, END)
if userfound == False and username != "admin":
lberror.config(text="Username not found, try again")
entuser.delete(0, END)
entpass.delete(0, END)
if access == True:
lberror.config(text= "Access Granted")
sleep(1)
mainlog.destroy()
return access
return mode
access = False
mode = "student"
mainlog = Tk()
mainlog.title("Maths Quiz Login")
lbuser = Label(mainlog, text= "Username: ")
lbpass = Label(mainlog, text= "Password: ")
entuser = Entry(mainlog,)
entpass = Entry(mainlog, show="*")
logbtn = Button(mainlog, text= "Login", command= checklogin)
lberror = Label(mainlog, text= "")
lbuser.grid(row=0, column=0)
lbpass.grid(row=1, column=0)
entuser.grid(row=0, column=1)
entpass.grid(row=1, column=1)
logbtn.grid(row=2, column=1)
lberror.grid(row=3,column = 0, columnspan = 2)
mainlog.geometry("250x150+100+100")
mainlog.mainloop()
当我尝试运行代码时,lberror
标签似乎服从所有命令,当相应事件发生时显示不正确的密码或未找到用户名,但它未能显示已授予访问权限,我试图寻找解释但我不能设法找到。