6

我有一些问题。我正在研究并尝试所有建议，但没有一项工作。

我最终得到：

Argument 1 passed to Entity\User::addCategories() must be an instance of Entity\Category, string given,

我有很多关系、用户、user_category 和类别

用户

<?php

namespace Entity;

use Doctrine\Common\Collections\ArrayCollection;

use Gedmo\Mapping\Annotation as Gedmo;
use Doctrine\ORM\Mapping as ORM;

/**
 * @Entity
 * @Table(name="user")
 */
class User
{

    /**
     * @Id
     * @Column(type="integer", nullable=false)
     * @GeneratedValue(strategy="AUTO")
     */
    public $id;

    /**
     * @Column(type="string", length=255, unique=true, nullable=false)
     */
    public $name;


    /**
     * @ManyToMany(targetEntity="Entity\Category", inversedBy="user")
     * @ORM\JoinTable(name="user_category")
     */
    public $categories;

        public function __construct() {
            $this->category = new \Doctrine\Common\Collections\ArrayCollection();
    }

    public function getCategories()
    {
        return $this->categories;
    }

    public function addCategories(Category $category = null)
    {
        $this->categories = $category;
    }

    public function setName($name)
    {
        $this->name = $name;
    }
    public function getName()
    {
        return $this->name;
    }

}

类别

<?php

namespace Entity;

use Doctrine\Common\Collections\ArrayCollection;

use Gedmo\Mapping\Annotation as Gedmo;
use Doctrine\ORM\Mapping as ORM;

/**
 * @Entity
 * @Table(name="category")
 */
class Category
{

    /**
     * @Id
     * @Column(type="integer", nullable=false)
     * @GeneratedValue(strategy="AUTO")
     */
    public $id;

    /**
     * @Column(type="string", length=255, unique=true, nullable=false)
     */
    public $name;

    /**
     * @ManyToMany(targetEntity="Entity\User", mappedBy="category")
     */
    public $user;


    public function __construct() {
        $this->user = new \Doctrine\Common\Collections\ArrayCollection();
    }

    public function getUser()
    {
        return $this->user;
    }

    public function addUser(User $user = null)
    {
        $user->addCategory($this);
        $this->user = $user;
    }


    public function setName($name)
    {
        $this->name = $name;
    }
    public function getName()
    {
    return $this->name;
    }
}

插入功能

        // check existence object in database
        $res = $this->em->find('Entity\User', $this->input->post('id'));

        if($res){
            $data = $this->em->find('Entity\User', $this->input->post('id'));
        }else{
            // create a new User object
            $data = new Entity\User;                
        }


        $data->setName($this->input->post('name'));
        $data->addCategories($this->input->post('category'));


        // save the data object to the database
        $this->em->persist($data);

        $this->em->flush();

一切都很顺利，但我对设置工作感到很困惑。

谢谢你的帮助。对不起我的英语不好。

4

1 回答 1

10

你有很多错误（注意语法）：

代替

public $categories;
public function __construct() {
    $this->category = new \Doctrine\Common\Collections\ArrayCollection();
}

它应该是：

protected $categories;

public function __construct() {
    $this->categories = new \Doctrine\Common\Collections\ArrayCollection();
}

代替：

public $user;
public function __construct() {
    $this->user = new \Doctrine\Common\Collections\ArrayCollection();
}

采用

protected $users;
public function __construct() {
    $this->users = new \Doctrine\Common\Collections\ArrayCollection();
}

代替

public function addCategories(Category $category = null)
{
    $this->categories = $category;
}

一定是

public function addCategory(Category $category = null)
{
    $this->categories->add($category);
}

和

public function removeCategory(Category $category)
{
    $this->categories->removeElement($category) ;
}
public function setCategories($categories)
{
    $this->categories = categories;
}

双方逻辑相同。我不知道 CI 是如何工作的，但 Symfony 会自动找到 addSomething/removeSomething 方法。即使 CI 不支持该功能，您仍应按上述方式更改代码。

于 2013-06-16T09:59:33.057 回答